#include typedef long long ll; typedef long double ld; const int INF=1e9,MOD=1e9+7,ohara=1e6+10; const ll LINF=1e18; using namespace std; #define rep(i,n) for(ll (i)=0;(i)<(int)(n);(i)++) #define rrep(i,a,b) for(ll i=(a);i<(b);i++) #define rrrep(i,a,b) for(ll i=(a);i>=(b);i--) #define all(v) (v).begin(), (v).end() #define Size(n) (n).size() #define Cout(x) cout<<(x)< #define m_p make_pair #define V vector #define U_MAP unordered_map #define pq priority_queue #define rpq priority_queue,greater> #define p_b push_back ll n,cnt,ans,a,b,c,d,tmp,tmpp,m,h,w,x,y,sum,pos,k,q; ld doua; int dy[]={1,0,-1,0}; int dx[]={0,1,0,-1}; //int dy[]={-1,0,1,-1,1,-1,0,1}; //int dx[]={-1,-1,-1,0,0,1,1,1}; string alph("abcdefghijklmnopqrstuvwxyz"),s; bool fl; struct edge{int to,cost;}; //------ Believe yourself as a genius!!!!!! ------ int main(void){ cin.tie(0); cout.tie(0); ios::sync_with_stdio(false); cin>>q; while(1){ cin>>a>>b>>c; ans=0; if(c==1){ Cout(-1); } else{ ll now=a; while(1){ if(now==0)break; if(now%c==0){ now/=c; ans+=b; } else{ ll cou1=0,cou2=0; ll want=now-now%c; ll cost=(now-want)/(c-1); if((now-want)%(c-1)!=0)cost++; cou1+=b*cost; cost=(now)/(c-1); if((now)%(c-1)!=0)cost++; cou2+=b*cost; if(want-want/c>c-1)ans+=cou1,now=want; else ans+=cou2,now=0; } } Cout(ans); } q--; if(q==0)break; } return 0; }