#include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define MOD (long long int)(1e9+7) #define ll long long int #define rep(i,n) for(int i=0; i<(int)(n); i++) #define reps(i,n) for(int i=1; i<=(int)(n); i++) #define REP(i,n) for(int i=n-1; i>=0; i--) #define REPS(i,n) for(int i=n; i>0; i--) #define INF (int)(1123456789) #define LINF (long long int)(1e18+1) #define chmax(a, b) a = (((a)<(b)) ? (b) : (a)) #define chmin(a, b) a = (((a)>(b)) ? (b) : (a)) #define all(v) v.begin(), v.end() const int N = (int)3e5; ll mpow(ll a, ll b){ if(b==0) return 1; else if(b%2==0){ll memo = mpow(a,b/2); return memo*memo%MOD;} else return mpow(a,b-1) * a % MOD; } ll lpow(ll a, ll b){ if(b==0) return 1; else if(b%2==0){ll memo = lpow(a,b/2); return memo*memo;} else return lpow(a,b-1) * a; } ll gcd(ll a, ll b){ if(b==0) return a; else return gcd(b, a%b); } vector kaijo_memo; ll kaijo(ll n){ if(kaijo_memo.size() > n) return kaijo_memo[n]; if(kaijo_memo.size() == 0) kaijo_memo.push_back(1); while(kaijo_memo.size() <= n) kaijo_memo.push_back(kaijo_memo[kaijo_memo.size()-1] * kaijo_memo.size() % MOD); return kaijo_memo[n]; } vector gyaku_kaijo_memo; ll gyaku_kaijo(ll n){ if(gyaku_kaijo_memo.size() > n) return gyaku_kaijo_memo[n]; if(gyaku_kaijo_memo.size() == 0) gyaku_kaijo_memo.push_back(1); while(gyaku_kaijo_memo.size() <= n) gyaku_kaijo_memo.push_back(gyaku_kaijo_memo[gyaku_kaijo_memo.size()-1] * mpow(gyaku_kaijo_memo.size(), MOD-2) % MOD); return gyaku_kaijo_memo[n]; } ll nCr(ll n, ll r){ if(n == r) return 1;//0個の丸と-1個の棒みたいな時に時に効く?不安. if(n < r || r < 0) return 0; ll ret = 1; ret *= kaijo(n); ret %= MOD; ret *= gyaku_kaijo(r); ret %= MOD; ret *= gyaku_kaijo(n-r); ret %= MOD; return ret; } multiset s,kind; int main(void){ ll n;cin>>n; vector A; rep(i,n){ ll a; cin>>a; A.push_back(a); } ll ans = 0; rep(i,n){ ll a = A[i]; vector memo; reps(p,(ll)sqrt(a+0.1)+10){ if(p==1) continue; if(a%p == 0){ while(a%p == 0){ a /= p; } memo.push_back(p); } } if(a != 1){ memo.push_back(a); } rep(b, lpow(2,memo.size())){ ll mul = 1; ll pc = 0; rep(j, memo.size()){ if((b>>j)&1){ mul *= memo[j]; pc++; } } ll count = 0; rep(j,n){ if(j <= i) continue; if(A[j]%mul == 0){ count++; } } ans += lpow(2,count) * (pc%2==0?1:-1); } } cout<