a = gets.split.map(&:to_i)
b = []
a[0].times do
  b << gets.split.map(&:to_i)
end

memo = [b.first]
a[0].times do |n|
  memo.last.uniq!
  tmp = []
  a[1].times do |m|
    break unless b[n+1]
    memo.last.length.times do |l|
      sum = memo[n][l] + b[n+1][m]
      sum <= a[2] ? tmp << sum : next
    end
  end
  memo << tmp unless tmp.empty?
end
# p memo

p memo.count == 1 ? -1 : a[2] - memo.last.max