B = Array.new(10){ Array.new(10) }
B[2][8] = 'A'
B[3][9] = 'B'
B[7][9] = 'C'

N = gets.to_i
N.times do
  sx,sy,tx,ty = gets.split.map(&:to_i)
  B[tx][ty] = B[sx][sy]
  B[sx][sy] = nil
end
puts [B[5][8] == 'A', B[4][8] == 'B', B[6][8] == 'C'].all? ? 'Yes' : 'No'