def order(n)
  case n % 10
  when 1; "#{n}st"
  when 2; "#{n}nd"
  when 3; "#{n}rd"
  else; "#{n}th"
  end
end

H, N = gets.split.map(&:to_i)
S = Array.new(N + 1, H)
(1 .. N).each{|i|S[i] = gets.to_i}
S.sort!.reverse!
puts order(S.index(H) + 1)