def solve(S, string1, string2):
    n = len(S)
    len1 = len(string1)
    len2 = len(string2)
    dp1 = [0] * n # good
    dp2 = [0] * n # problem
    dp1[len1-1] = len1
    dp2[n-len2+1] = len2
    for tail in range(len1, n-len2 + 1):
        dist = len([1 for c1, c2 in zip(string1, S[tail - len1:tail]) if c1 != c2])
        dp1[tail] = min(dp1[tail - 1], dist)
        if not dp1[tail]:
            break        
    for head in range(n-len2, len1 - 1, -1):
        dist = len([1 for c1, c2 in zip(string2, S[head:head + len2]) if c1 != c2])
        dp2[head] = min(dp2[head + 1], dist)
        if not dp2[head]:
            break
    dp3 = [0] * n  # number of string2 in S[:i-len1]
    for i in range(len1 + len2, n - len2 + 1):
        if string2 == S[i-len1-len2:i-len1]:
            dp3[i] = dp3[i-1] + 1
        else:
            dp3[i] = dp3[i-1]
    return min(dp1[i] + dp2[i] + dp3[i] for i in range(len1, n - len2 + 1))
        

T = int(input())
for t in range(T):
    print(solve(input(), 'good', 'problem'))