#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

int N,Q;
ll A[202020];
int L[202020],R[202020];
ll ret[202020],M[202020];

template<class V,int NV> class SegTree_1 {
public:
	vector<vector<V>> val;
	static V const def=0;
	V comp(V l,V r){ return max(l,r);};
	
	SegTree_1(){val.resize(NV*2);};
	V getval(int x,int y,V v,int l=0,int r=NV,int k=1) { // x<=i<y
		if(r<=x || y<=l) return 0;
		if(x<=l && r<=y) {
			return lower_bound(ALL(val[k]),v+1)-val[k].begin();
		}
		return getval(x,y,v,l,(l+r)/2,k*2)+getval(x,y,v,(l+r)/2,r,k*2+1);
	}
	void set(int entry,V v) {
		val[entry+NV].clear();
		val[entry+NV].push_back(v);
	}
	void build() {
		for(int i=NV-1;i>=1;i--) {
			val[i].clear();
			int a=0,b=0;
			int x=i*2,y=i*2+1;
			while(a<val[x].size() || b<val[y].size()) {
				if(a==val[x].size()) {
					val[i].push_back(val[y][b++]);
				}
				else if(b==val[y].size()) {
					val[i].push_back(val[x][a++]);
				}
				else if(val[x][a]<val[y][b]) {
					val[i].push_back(val[x][a++]);
				}
				else {
					val[i].push_back(val[y][b++]);
				}
			}
		}
	}
};

template<class V, int ME> class BIT {
public:
	V bit[1<<ME];
	V operator()(int e) {if(e<0) return 0;V s=0;e++;while(e) s+=bit[e-1],e-=e&-e; return s;}
	void add(int e,V v) { e++; while(e<=1<<ME) bit[e-1]+=v,e+=e&-e;}
};
BIT<ll,18> bt;

SegTree_1<int,1<<18> st;
pair<ll,int> P[202020];
vector<int> ev[202020];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>Q;
	FOR(i,N) {
		cin>>A[i];
		P[i]={A[i],i};
	}
	sort(P,P+N);
	FOR(i,N) {
		st.set(P[i].second,i);
	}
	
	st.build();
	FOR(i,Q) {
		cin>>L[i]>>R[i];
		L[i]--;
		M[i]=N-1;
		for(j=17;j>=0;j--) if(M[i]-(1<<j)>=0) {
			if(st.getval(L[i],R[i],P[M[i]-(1<<j)].first)>=(R[i]-L[i]+1)/2) M[i]-=1<<j;
		}
		ev[M[i]].push_back(i);
		ll v=P[M[i]].first>>20;
		ret[i]+=1LL*((R[i]-L[i]+1)/2)*v-1LL*(R[i]-L[i]-(R[i]-L[i]+1)/2)*v;
	}
	FOR(i,N) {
		bt.add(P[i].second,A[P[i].second]);
		FORR(e,ev[i]) {
			ret[e]-=2*(bt(R[e]-1)-bt(L[e]-1));
		}
	}
	
	FOR(i,Q) {
		ret[i]+=bt(R[i]-1)-bt(L[i]-1);
		cout<<ret[i]<<endl;
	}
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}