/* このコード、と~おれ! Be accepted! ∧_∧ (。・ω・。)つ━☆・*。 ⊂ ノ ・゜+. しーJ °。+ *´¨) .· ´¸.·*´¨) ¸.·*¨) (¸.·´ (¸.·'* ☆ */ #include #include #include #include #include #include #include #include #include #include #include #include #pragma GCC optimize("Ofast") #define rep(i, n) for(int i = 0; i < (n); ++i) #define rep1(i, n) for(int i = 1; i <= (n); ++i) #define rep2(i, n) for(int i = 2; i < (n); ++i) #define repr(i, n) for(int i = n; i >= 0; --i) #define reprm(i, n) for(int i = n - 1; i >= 0; --i) #define printynl(a) printf(a ? "yes\n" : "no\n") #define printyn(a) printf(a ? "Yes\n" : "No\n") #define printYN(a) printf(a ? "YES\n" : "NO\n") #define printin(a) printf(a ? "possible\n" : "inposible\n") #define printdb(a) printf("%.50lf\n", a)//少数出力 #define printdbd(a) printf("%.16lf\n", a)//少数出力(桁少なめ) #define prints(s) printf("%s\n", s.c_str())//string出力 #define all(x) (x).begin(), (x).end() #define allsum(a, b, c) ((a + b) * c / 2)//等差数列の和、初項,末項,項数 #define pb push_back #define priq priority_queue #define rpriq priq, greater> #define deg_to_rad(deg) (((deg)/360.0)*2.0*PI) #define rad_to_deg(rad) (((rad)/2.0/PI)*360.0) #define Please return #define AC 0 using ll = long long; const int INF = 1073741823; const int MINF = -1073741823; const ll LINF = ll(4661686018427387903); const ll MOD = 1000000007; const double PI = acos(-1); using namespace std; void scans(string& str) { char c; scanf("%c", &c); if (c == '\n')scanf("%c", &c);//最初の改行対策 while (c != '\n' && c != -1) { str += c; scanf("%c", &c); } } void scanc(char& str) { char c; scanf("%c", &c); if (c == -1)return; while (c == '\n') { scanf("%c", &c); } str = c; } double acot(double x) { return PI / 2 - atan(x); } /*-----------------------------------------ここからコード-----------------------------------------*/ int main() { int n; scanf("%d", &n); string s; scans(s); vector a(n); rep(i, n)scanf("%lld", &a[i]); ll right = 0, left = 0; int q; scanf("%d", &q); ll k; ll sum = 0, enemy = 0, ans = MINF; rep(qq, q) { right = left = sum = enemy = 0; ans = MINF; scanf("%lld", &k); for (left = 0; left < n; ++left) { while (right < n && sum + a[right] <= k) { sum += a[right]; enemy += (s[right] == 'E'); ++right; } ans = max(ans, enemy); if (right == left) { ++right; }else{ sum -= a[left]; enemy -= (s[left] == 'E'); } } printf("%lld\n", ans); } Please AC; }