#include <iostream>
using namespace std;
typedef long long ll;

int main(){
	ll N, K;
	cin >> N >> K;

	ll curr = (N - 1) % (K + 1);
	for(;;){
		cout << curr << endl;
		curr += K + 1;

		ll res;
		cin >> res;
		if(res >= N){
			break;
		}
	}
	return 0;
}