/* #region Head */ //============================================================================ // Name : filename.cpp // Author : abb // Version : // Copyright : [My copyright notice] // Description : test program //============================================================================ #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include using namespace std; using ll = long long; using ull = unsigned long long; using pll = pair; using vll = vector; using vvll = vector; using vd = vector; using vvd = vector; using vs = vector; using vvs = vector; #define REP(i, m, n) for (ll i = (m), i##_len = (ll)(n); i < i##_len; ++(i)) #define REPM(i, m, n) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; ++(i)) #define REPR(i, m, n) for (ll i = (m), i##_min = (ll)(n); i >= i##_min; --(i)) #define REPD(i, m, n, d) for (ll i = (m), i##_len = (ll)(n); i < i##_len; i += (d)) #define REPMD(i, m, n, d) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; i += (d)) #define REPI(itr, ds) for (auto itr = ds.begin(); itr != ds.end(); itr++) #define ALL(x) begin(x), end(x) #define SIZE(x) ((ll)(x).size()) constexpr ll INF = 1'010'000'000'000'000'017LL; constexpr ll MOD = 1'000'000'007LL; // 1e9 + 7 constexpr double EPS = 1e-12; constexpr double PI = 3.14159265358979323846; // vector入力 template istream &operator>>(istream &is, vector &vec) { for (T &x : vec) is >> x; return is; } // vector出力 template ostream &operator<<(ostream &os, vector &vec) { ll len = SIZE(vec); os << "{"; for (int i = 0; i < len; i++) os << vec[i] << (i == len - 1 ? "" : ", "); os << "}"; return os; } // pair入力 template istream &operator>>(istream &is, pair &pair_var) { is >> pair_var.first >> pair_var.second; return is; } // pair出力 template ostream &operator<<(ostream &os, pair &pair_var) { os << "(" << pair_var.first << ", " << pair_var.second << ")"; return os; } // map出力 template ostream &operator<<(ostream &os, map &map_var) { os << "{"; REPI(itr, map_var) { os << *itr; itr++; if (itr != map_var.end()) os << ", "; itr--; } os << "}"; return os; } // set 出力 template ostream &operator<<(ostream &os, set &set_var) { os << "{"; REPI(itr, set_var) { os << *itr; itr++; if (itr != set_var.end()) os << ", "; itr--; } os << "}"; return os; } // dump #define DUMPOUT cerr void dump_func() { DUMPOUT << endl; } template void dump_func(Head &&head, Tail &&... tail) { DUMPOUT << head; if (sizeof...(Tail) > 0) { DUMPOUT << ", "; } dump_func(move(tail)...); } // chmax (更新「される」かもしれない値が前) template > bool chmax(T &xmax, const U &x, Comp comp = {}) { if (comp(xmax, x)) { xmax = x; return true; } return false; } // chmin (更新「される」かもしれない値が前) template > bool chmin(T &xmin, const U &x, Comp comp = {}) { if (comp(x, xmin)) { xmin = x; return true; } return false; } // container 内の最初の element のインデックスを探す template ll indexof(const Container &container, const typename Container::value_type &element) { auto iter = find(container.begin(), container.end(), element); size_t index = distance(container.begin(), iter); if (index == container.size()) { index = -1; } return index; } // ローカル用 #define DEBUG_ #ifdef DEBUG_ #define DEB #define dump(...) \ DUMPOUT << " " << string(#__VA_ARGS__) << ": " \ << "[" << to_string(__LINE__) << ":" << __FUNCTION__ << "]" \ << endl \ << " ", \ dump_func(__VA_ARGS__) #else #define DEB if (false) #define dump(...) #endif struct AtCoderInitialize { static constexpr int IOS_PREC = 15; static constexpr bool AUTOFLUSH = false; AtCoderInitialize() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); cout << fixed << setprecision(IOS_PREC); if (AUTOFLUSH) cout << unitbuf; } } ATCODER_INITIALIZE; /* #endregion */ /** 非負整数の組 (X, Y) であって、X <= Y かつ X ∧ Y=A かつ X ∨ Y=B を満たすものの個数を求めてください。 ここで、∧ はビット毎の論理積を、∨ はビット毎の論理和を意味します。 */ void solve() { ll a, b; // <= 2^{31} (32 bit) cin >> a >> b; // A, B のある桁の bit a, b から,もとの数 X, Y の対応する bit x, y を推定すると, // (a, b) = (1, 1) -> (x, y) = (1, 1) // (a, b) = (0, 0) -> (x, y) = (0, 0) // (a, b) = (0, 1) -> (x, y) = (0, 1), (1, 0) // (a, b) = (1, 0) -> (x, y) = なし ll pat = 1, ai, bi; REP(i, 0, 32) { ai = (a >> i) & 1; bi = (b >> i) & 1; // dump(ai, bi); if (!ai && bi) pat *= 2; else if (ai && !bi) { pat = 0; break; } } if (pat > 1) pat /= 2; cout << pat << endl; } /** * エントリポイント. * @return 0. */ int main() { solve(); return 0; }