#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

ll N,K;

vector<ll> R[202020];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>K;
	ll sum=N*(N+1)/2;
	if(sum%K) return _P("No\n");
	
	if(N/K%K==0) {
		FOR(i,N/K) {
			FOR(j,K) {
				R[(i+j)%K].push_back(i*K+j+1);
			}
		}
	}
	else if(N/K%2==0) {
		FOR(i,N/K) {
			FOR(j,K) {
				if(i%2==0) R[j].push_back(i*K+j+1);
				else R[K-1-j].push_back(i*K+j+1);
			}
		}
	}
	else {
		return _P("No\n");
	}
	cout<<"Yes"<<endl;
	FOR(i,K) {
		FORR(c,R[i]) cout<<c<<" ";
		cout<<endl;
	}
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}