#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using namespace placeholders; using LL = long long; using ULL = unsigned long long; using VI = vector< int >; using VVI = vector< vector< int > >; using VS = vector< string >; using SS = stringstream; using PII = pair< int, int >; using VPII = vector< pair< int, int > >; template < typename T = int > using VT = vector< T >; template < typename T = int > using VVT = vector< vector< T > >; template < typename T = int > using LIM = numeric_limits< T >; template < typename T > inline istream& operator>>( istream &s, vector< T > &v ){ for ( T &t : v ) { s >> t; } return s; } template < typename T > inline ostream& operator<<( ostream &s, const vector< T > &v ){ for ( int i = 0; i < int( v.size() ); ++i ){ s << ( " " + !i ) << v[i]; } return s; } template < typename T > inline T fromString( const string &s ) { T res; istringstream iss( s ); iss >> res; return res; }; template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); }; #define REP2( i, n ) REP3( i, 0, n ) #define REP3( i, m, n ) for ( int i = ( int )( m ); i < ( int )( n ); ++i ) #define GET_REP( a, b, c, F, ... ) F #define REP( ... ) GET_REP( __VA_ARGS__, REP3, REP2 )( __VA_ARGS__ ) #define FOR( e, c ) for ( auto &e : c ) #define ALL( c ) ( c ).begin(), ( c ).end() #define AALL( a, t ) ( t* )a, ( t* )a + sizeof( a ) / sizeof( t ) #define DRANGE( c, p ) ( c ).begin(), ( c ).begin() + ( p ), ( c ).end() #define SZ( v ) ( (int)( v ).size() ) #define PB push_back #define EM emplace #define EB emplace_back #define BI back_inserter #define EXIST( c, e ) ( ( c ).find( e ) != ( c ).end() ) #define MP make_pair #define fst first #define snd second #define DUMP( x ) cerr << #x << " = " << ( x ) << endl constexpr int MOD = 1000000007; int dp[ 1 << 14 ][ 32 ][ 2 ][ 2 ]; int solve( const string &S ) { const int L = SZ( S ); fill( AALL( dp, int ), 0 ); dp[0][0][0][0] = 1; // dp[ 桁数 ][ mod 24 ][ includes 3 ][ less S ] REP( i, L ) { const int D = S[i] - '0'; REP( j, 24 ) { REP( k, 2 ) { REP( l, 2 ) { REP( d, l ? 10 : D + 1 ) { ( dp[ i + 1 ][ ( j * 10 + d ) % 24 ][ k || d == 3 ][ l || d < D ] += dp[i][j][k][l] ) %= MOD; } } } } } int res = 0; REP( j, 24 ) { REP( k, 2 ) { REP( l, 2 ) { if ( ( j % 3 == 0 || k ) && j % 8 ) { ( res += dp[L][j][k][l] ) %= MOD; } } } } return res; } int main() { cin.tie( 0 ); ios::sync_with_stdio( false ); string A, B; cin >> A >> B; { int i; for ( i = SZ( A ) - 1; A[i] == '0'; --i ); // --A[i]; for ( ; i < SZ( A ); i++ ) { A[i] = A[i] == '0' ? '9' : A[i] - 1; } for ( i = 0; i < SZ( A ) && A[i] == '0'; ++i ); A = A.substr( i ); } cout << ( solve( B ) + MOD - solve( A ) ) % MOD << endl; return 0; }