#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; #define sz size() #define pb push_back #define mp make_pair #define fi first #define se second #define all(c) (c).begin(), (c).end() #define rep(i,a,b) for(ll i=(a);i<(b);++i) #define per(i,a,b) for(ll i=b-1LL;i>=(a);--i) #define clr(a, b) memset((a), (b) ,sizeof(a)) #define ctos(c) string(1,c) #define print(x) cout<<#x<<" = "< struct time_array{ private: int t; vector ts; vector v; public: time_array() {} time_array(int n) : t(0), ts(n, 0), v(n) { } T& operator[](int i) { if (ts[i] < t) { ts[i] = t; v[i] = T(); } return v[i]; } int size() const { return v.size(); } void clear() { ++t; } }; struct segsum{ long long nn; time_array dat1; time_array dat2; segsum(int n): dat1(n), dat2(n){} void init(long long n1){ nn = 1; while(nn < n1)nn *= 2; dat1.clear(); dat2.clear(); } void add(long long a, long long b, long long x, long long k, long long l, long long r) { if (a <= l && r <= b) { dat1[k] += x; } else if (l < b && a < r) { dat2[k] += (min(b, r) - max(a, l)) * x; add(a, b, x, k * 2 + 1, l, (l + r) / 2); add(a, b, x, k * 2 + 2, (l + r) / 2, r); } } long long sum(long long a, long long b, long long k, long long l, long long r){ if (b <= l || r <= a)return 0LL; else if (a <= l && r <= b) { return (dat1[k] * (r - l) + dat2[k]); } else { long long ret; ret = (min(b, r) - max(a, l)) * dat1[k]; ret += sum(a, b, k * 2 + 1, l, (l + r) / 2); ret += sum(a, b, k * 2 + 2, (l + r) / 2, r); return ret; } } void add(long long a, long long b, long long x){ return add(a,b,x,0,0,nn); } long long sum(long long a, long long b){ return sum(a,b,0,0,nn); } }; int main(){ ll n; cin>>n; vector > vv(100100,vector()); rep(i,0,n){ ll a; cin>>a; a--; vv[a].pb(i); } ll ans = 0; time_array ta(1<<19); segsum segsum1(1<<20); rep(i,0,vv.sz){ vv[i].pb(n); ll p = 1<<17; ta.clear(); segsum1.init(1<<19); ll now = -1; rep(j,0,vv[i].sz){ ll nex = vv[i][j]; ll a = nex-now-1; ans += ta[p-2]-ta[p-a-2]; segsum1.add(p-a+1,p+1,1); p -= a; if(j!=vv[i].sz-1){ segsum1.add(p,p+1,1); ans += segsum1.sum(0,p+1); ta[p] = ta[p-1]+segsum1.sum(0,p+1); p++; } now = nex; } } cout << ans << endl; return 0; }