#include #include #include #include #include #define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() const int INF = 0x3f3f3f3f; const long long LINF = 0x3f3f3f3f3f3f3f3fLL; const double EPS = 1e-8; const int MOD = 1000000007; // const int MOD = 998244353; const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; // const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1}, // dx[] = {0, -1, -1, -1, 0, 1, 1, 1}; struct IOSetup { IOSetup() { cin.tie(nullptr); ios_base::sync_with_stdio(false); cout << fixed << setprecision(20); cerr << fixed << setprecision(10); } } iosetup; /*-------------------------------------------------*/ int main() { int n, k; cin >> n >> k; vector > pd(n); REP(i, n) cin >> pd[i].first >> pd[i].second; sort(pd.rbegin(), pd.rend()); vector > > dp(2, vector >(k + 1, vector(2, -INF))); dp[0][0][false] = 0; REP(i, n) REP(j, k + 1) { REP(l, 2) dp[(i + 1) & 1][j][l] = max(dp[(i + 1) & 1][j][l], dp[i & 1][j][l]); if (j + pd[i].first <= k) dp[(i + 1) & 1][j + pd[i].first][true] = max(dp[(i + 1) & 1][j + pd[i].first][true], dp[i & 1][j][false] + pd[i].second); dp[(i + 1) & 1][j][false] = max(dp[(i + 1) & 1][j][false], dp[i & 1][j][true] + pd[i].second); } int ans = 0; REP(j, k + 1) ans = max({ans, dp[n & 1][j][false], dp[n & 1][j][true]}); cout << ans << '\n'; return 0; }