#include <stdio.h>
#include <string>
#include <cstring>
#include <stdlib.h>
#include <math.h>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <iterator>
#include <assert.h>
#pragma warning(disable:4996) 
 
typedef long long ll;
#define MIN(a, b) ((a)>(b)? (b): (a))
#define MAX(a, b) ((a)<(b)? (b): (a))
#define LINF 9223300000000000000
#define INF 2140000000
const long long MOD = 1000000007;
//const long long MOD = 998244353;
using namespace std;

ll dp[3005][3005];     // dp[i][j] i番目(0,1,..i-1)まで見て、j個閉じている場合の危険度の最小値

int main(int argc, char* argv[])
{
    int n;
    scanf("%d%", &n);
    vector<ll> A(n),S(n+1);
    int i,j;
    for(i=0; i<n; i++) {
        scanf("%lld", &A[i]);
        S[i+1]=S[i]+A[i];
    }

    vector<ll> a(n+1),b(n+1);

    const double eps=1e-6;
    for(j=0; j<=n; j++) {
        if(j==0) {
            for(i=0; i<=n; i++) {
                dp[i][j]=S[i]*S[i];
            }
        }
        else {
            vector<pair<double,int> > z;    // xの値, xより少し大きいところの直線のindex
            for(i=j; i<=n; i++) {
                {
                    // for CHT
                    a[i]=-2*S[i];
                    b[i]=dp[i-1][j-1]+S[i]*S[i];

                    while( 1 ) {
                        if(z.empty()) {
                            z.push_back(make_pair(-HUGE_VAL,i));
                            break;
                        }
                        else {
                            double  x0=z.back().first;
                            int id0=z.back().second;

                            double tmp=-(double)(b[i]-b[id0])/(a[i]-a[id0]);
                            if(tmp<x0) {
                                z.pop_back();
                            }
                            else {
                                z.push_back(make_pair(tmp,i));
                                break;
                            }
                        }
                    }
                }                
                
                if(i>j) {
                    ll tmp=0;
                    if(!z.empty()) {
                        int k=lower_bound(z.begin(), z.end(), make_pair((double)S[i]+eps,-INF))-z.begin();
                        if(k>0) {
                            k--;
                            int id=z[k].second;
                            tmp=a[id]*S[i]+b[id];
                        }
                    }
                    dp[i][j]=tmp+S[i]*S[i];
                }
            }
        }
    }
    for(i=0; i<n; i++) {
        printf("%lld\n", dp[n][n-1-i]);
    }

    return 0;
}