#include <bits/stdc++.h>
using namespace std;
#define REP(i,n) for (int i=0;i<(n);i++)
#define REP2(i,m,n) for (int i=m;i<(n);i++)
typedef long long ll;

const int SQ = 500;
const int OFFSET = 101010;

int N;
int A[101010];
int B[101010];
int C[101010];
ll D[202020];
int E[101010];
int cnt[101010];

void solve() {
    cin >> N;
    REP(i, N) cin >> A[i];
    REP(i, N) cnt[A[i]] += 1;

    vector<int> less, much;
    REP(i, 101010) if (cnt[i] > 0) (cnt[A[i]] < SQ ? less : much).push_back(i);
    REP(i, N) (cnt[A[i]] < SQ ? B[i] : C[i]) = A[i];

    int L = less.size();
    int M = much.size();
    ll ans = 0;

    REP2(len, 1, min(N+1, SQ*2)) {
        for (auto a : less) {
            E[a] = 0;
        }
        bool ok = false;
        const int half = len / 2 + 1;
        REP(i, len) if (B[i] != 0) {
            E[B[i]] += 1;
            if (E[B[i]] == half) ok = true;
        }
        ans += ok;
        REP2(i, 1, N-len+1) {
            if (i > 0 && B[i-1] != 0) {
                if (E[B[i-1]] == half) ok = false;
                E[B[i-1]] -= 1;
            }
            if (B[i+len-1] != 0) {
                E[B[i+len-1]] += 1;
                if (E[B[i+len-1]] == half) ok = true;
            }
            ans += ok;
        }
    }

    for (const auto a : much) {
        memset(D, 0, sizeof(D));
        int pointer = OFFSET;
        int counter = 0; // pointer 未満の合計
        D[OFFSET] += 1;
        REP(i, N) {
            if (A[i] == a) {
                pointer += 1;
                counter += D[pointer - 1];
            } else {
                pointer -= 1;
                counter += D[pointer - 1];
            }
            D[pointer] += 1;
            ans += counter;
        }
        //cout << pointer - OFFSET << " " << counter << " " << D[pointer] << endl;
    }

    cout << ans << endl;
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    solve();
}