#include <stdio.h>
#include <vector>
#include <math.h>
#include <complex>
using namespace std;

typedef long long int ll;
constexpr int kMod = int(1E9 + 7), kN = 262144;
constexpr double pi = acos(-1);
constexpr complex<double> one = complex<double>(1, 0), half = complex<double>(0.5, 0);

ll Pow(ll a, ll b) {
	ll ans = 1;
	while (b) {
		if (b & 1) ans = ans * a % kMod;
		a = a * a % kMod;
		b >>= 1;
	}
	return ans;
}


void FFT(vector<complex<double>> &v, bool on, int sz) {
	complex<double> wn, u, t, w, inv(1.0 / sz, 0);
	for (int i = 1, j = sz >> 1, k; i < (sz - 1); i++) {
		if (i < j) swap(v[i], v[j]);
		k = sz >> 1;
		while (j & k) {
			j ^= k;
			k >>= 1;
		}
		j |= k;
	}
	for (int i = 2; i <= sz; i <<= 1) {
		wn = on ? complex<double>(cos(2 * pi / i), -sin(2 * pi / i)) : complex<double>(cos(2 * pi / i), sin(2 * pi / i));
		for (int j = 0; j < sz; j += i) {
			w = 1;
			for (int k = j; k < j + (i >> 1); k++) {
				u = v[k];
				t = w * v[k + (i >> 1)];
				v[k] = u + t;
				v[k + (i >> 1)] = u - t;
				w *= wn;
			}
		}
	}
	if (on) for (int i = 0; i < sz; i++) v[i] *= inv;

}

int a[kN];
ll ts[kN];

bool Lesser(int ax, int ay, int bx, int by) {
	long double left = (ax + ay), right = (bx + by);
	left *= pow(ax, ay), right *= pow(bx, by);
	return left > right;
}

int main() {
	int n, l, r, nm;
	ll ans = 1, tmp = 1;
	vector<complex<double>> v(kN);
	scanf("%d", &n);
	for (int i = 1; i <= n; i++) scanf("%d", &a[i]);

	ts[0] = 0;
	for (int i = 1; i <= n; i++) ts[i] = (ts[i - 1] + a[i]) % (kMod - 1);
	
	for (int i = 1; i <= n; i++) v[a[i]] += one;
	FFT(v, false, kN);
	for (int i = 0; i < kN; i++) v[i] = v[i] * v[i];
	FFT(v, true, kN);
	for (int i = 1; i <= n; i++) v[a[i] << 1] -= one;
	for (int i = 1; i < kN; i++) v[i] *= half;

	
	for (int i = 1; i < kN; i++) tmp = tmp * Pow(i, ll(v[i].real() + 0.5)) % kMod;
	for (int i = 1; i <= n; i++) ans = ans * Pow(a[i], ts[n] - ts[i] + kMod - 1) % kMod;
	
	l = a[n - 1], r = a[n], nm = a[n];
	for (int i = n - 2; i >= 1; i--) {
		nm = min(nm, a[i + 1]);
		if (Lesser(l, r, a[i], nm)) {
			l = a[i];
			r = nm;
		}
	}


	ans = ans * tmp % kMod;
	printf("%lld\n", ans * Pow((l + r) * Pow(l, r) % kMod, kMod - 2) % kMod);
}