#include #define LLI long long int #define FOR(v, a, b) for(LLI v = (a); v < (b); ++v) #define FORE(v, a, b) for(LLI v = (a); v <= (b); ++v) #define REP(v, n) FOR(v, 0, n) #define REPE(v, n) FORE(v, 0, n) #define REV(v, a, b) for(LLI v = (a); v >= (b); --v) #define ALL(x) (x).begin(), (x).end() #define RALL(x) (x).rbegin(), (x).rend() #define ITR(it, c) for(auto it = (c).begin(); it != (c).end(); ++it) #define RITR(it, c) for(auto it = (c).rbegin(); it != (c).rend(); ++it) #define EXIST(c,x) ((c).find(x) != (c).end()) #define fst first #define snd second #define popcount __builtin_popcount #define UNIQ(v) (v).erase(unique(ALL(v)), (v).end()) #define bit(i) (1LL<<(i)) #ifdef DEBUG #include #else #define dump(...) ((void)0) #endif #define gcd __gcd using namespace std; template constexpr T lcm(T m, T n){return m/gcd(m,n)*n;} template void join(ostream &ost, I s, I t, string d=" "){for(auto i=s; i!=t; ++i){if(i!=s)ost< istream& operator>>(istream &is, vector &v){for(auto &a : v) is >> a; return is;} template bool chmin(T &a, const U &b){return (a>b ? a=b, true : false);} template bool chmax(T &a, const U &b){return (a void fill_array(T (&a)[N], const U &v){fill((U*)a, (U*)(a+N), v);} struct Init{ Init(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(12); cerr << fixed << setprecision(12); } }init; int dp[5010][5010][2]; template void sort_with_ord(const std::vector &ord, std::vector &a){ const int N = ord.size(); std::vector temp(N); for(int i = 0; i < N; ++i) temp[i] = a[ord[i]]; std::swap(a, temp); } int main(){ int N, K; while(cin >> N >> K){ vector P(N), D(N); REP(i,N) cin >> P[i] >> D[i]; vector ord(N); iota(ALL(ord), 0); sort(ALL(ord), [&](int i, int j){return P[i] > P[j];}); sort_with_ord(ord, P); sort_with_ord(ord, D); fill_array(dp, INT_MIN); dp[0][0][0] = 0; REP(i,N){ FORE(j,0,K){ chmax(dp[i+1][j][0], dp[i][j][0]); chmax(dp[i+1][j][1], dp[i][j][1]); if(j+P[i] <= K) chmax(dp[i+1][j+P[i]][1], dp[i][j][0] + D[i]); chmax(dp[i+1][j][0], dp[i][j][1] + D[i]); } } int ans = 0; FORE(j,0,K) chmax(ans, max(dp[N][j][0], dp[N][j][1])); cout << ans << endl; } return 0; }