# include "bits/stdc++.h" using namespace std; using LL = long long; using ULL = unsigned long long; const double PI = acos(-1); templateconstexpr T INF() { return ::std::numeric_limits::max(); } templateconstexpr T HINF() { return INF() / 2; } template T_char TL(T_char cX) { return tolower(cX); }; template T_char TU(T_char cX) { return toupper(cX); }; const int vy[] = { -1, -1, -1, 0, 1, 1, 1, 0 }, vx[] = { -1, 0, 1, 1, 1, 0, -1, -1 }; const int dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 }; int popcnt(unsigned long long n) { int cnt = 0; for (int i = 0; i < 64; i++)if ((n >> i) & 1)cnt++; return cnt; } int d_sum(LL n) { int ret = 0; while (n > 0) { ret += n % 10; n /= 10; }return ret; } int d_cnt(LL n) { int ret = 0; while (n > 0) { ret++; n /= 10; }return ret; } LL gcd(LL a, LL b) { if (b == 0)return a; return gcd(b, a%b); }; LL lcm(LL a, LL b) { LL g = gcd(a, b); return a / g*b; }; # define ALL(qpqpq) (qpqpq).begin(),(qpqpq).end() # define UNIQUE(wpwpw) sort(ALL((wpwpw)));(wpwpw).erase(unique(ALL((wpwpw))),(wpwpw).end()) # define LOWER(epepe) transform(ALL((epepe)),(epepe).begin(),TL) # define UPPER(rprpr) transform(ALL((rprpr)),(rprpr).begin(),TU) # define FOR(i,tptpt,ypypy) for(LL i=(tptpt);i<(ypypy);i++) # define REP(i,upupu) FOR(i,0,upupu) struct INIT{ INIT(){ std::ios::sync_with_stdio(false); std::cin.tie(0); cout << fixed << setprecision(13); } }INIT; bool iskado(int a, int b, int c){ if(a == b || a == c || b == c)return false; int num = a + b + c - max({a, b, c}) - min({a, b, c}); if(num == a || num == c)return true; return false; } int t; int a, b, c; void solve(){ cin >> a >> b >> c; int ans = HINF(); if(iskado(a, b, c)){ cout << 0 << endl; return; } if(a < b && b < c && a >= 2){ ans = min(ans, b - (a - 1)); } if(c < b && b < a && c >= 2){ ans = min(ans, b - (c - 1)); } if(a == b){ if(b - c == 1){ if(a >= 3)ans = min(ans, 2); } else if(b == c){ if(a >= 3)ans = min(ans, 3); } else{ ans = min(ans, 1); } } if(b == c){ if(b - a == 1){ if(c >= 3)ans = min(ans, 2); } else if(b == a){ if(c >= 3)ans = min(ans, 3); } else{ ans = min(ans, 1); } } if(a == c){ if(b > a && a >= 2){ ans = min(ans, 1); } if(b >= 2 && a >= 3){ ans = min(ans, b - (a - 2) + 1); } } cout << (ans == HINF() ? -1 : ans) << endl; } int main(){ cin >> t; REP(ttt, t)solve(); }