#pragma GCC optimize("Ofast","unroll-loops") //#pragma GCC push_options //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include #include #include using namespace::std; __attribute__((constructor))void init(){cin.tie(0);ios::sync_with_stdio(false);cout< #include #include #include templateusing pbds=__gnu_pbds::tree,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; templateusing pbds_map=__gnu_pbds::tree,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>; templateusing hash_map=__gnu_pbds::gp_hash_table; templateusing pqueue =__gnu_pbds::priority_queue,__gnu_pbds::rc_binomial_heap_tag>; typedef long long lint; #define INF (1LL<<60) #define IINF (1<<30) #define EPS (1e-10) #define MOD 1000000007LL typedef vector vec; typedef vector> mat; typedef vector svec; typedef vector> smat; templateinline void numout(T t){bool f=0;for(auto i:t){cout<<(f?" ":"")<inline void numout2(T t){for(auto i:t)numout(i);} templateinline void output(T t){bool f=0;for(auto i:t){cout<<(f?" ":"")<inline void output2(T t){for(auto i:t)output(i);} templateinline void _output(T t){bool f=0;for(lint i=0;iinline void _output2(T t){for(lint i=0;i=0;--i) #define rrepi(i,a,b) for(lint i=lint(b)-1;i>=lint(a);--i) #define irep(i) for(lint i=0;;++i) #define all(n) begin(n),end(n) #define dist(a,b,c,d) sqrt(pow(a-c,2)+pow(b-d,2)) inline lint gcd(lint A,lint B){return B?gcd(B,A%B):A;} inline lint lcm(lint A,lint B){return A/gcd(A,B)*B;} inline bool chmin(auto& s,const auto& t){bool res=s>t;s=min(s,t);return res;} inline bool chmax(auto& s,const auto& t){bool res=s dx={1,0,-1,0,1,1,-1,-1}; const vector dy={0,1,0,-1,1,-1,1,-1}; #define SUM(v) accumulate(all(v),0LL) auto call=[](auto f,auto... args){return f(f,args...);}; lint bs(lint ok,lint ng,function func) { if(ok>ng){ok++;ng--;} else {ok--;ng++;} while(abs(ok-ng)>1){ lint mid=(ng+ok)/2; if(func(mid))ok=mid; else ng=mid; } return ok; } int main(){ lint n; cin>>n; vec a(n),v(n+1); rep(i,n)cin>>a[i]; sort(all(a)); v[0]=1; rep(i,n)v[i+1]=v[i]+a[i]; lint ans=0; rep(i,n){ lint x=bs(1,min(n-i-1,i),[&](lint x){ return a[n-x]+a[i-x]>=2*a[i]; }); if(x!=0)chmax(ans,v[n]-v[n-x]+v[i]-v[i-x]-x*2*a[i]); } cout<