#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
#include <cmath>
#include <bitset>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <algorithm>
#include <complex>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <cassert>
#include <fstream>
#include <utility>
#include <functional>
#include <time.h>
#include <stack>
#include <array>
#define popcount __builtin_popcount
using namespace std;
typedef long long int ll;
typedef pair<ll, ll> P;

int main()
{
	int w;
	cin>>w;
	ll a[55], b[55], c[55], x[55];
	ll sa=0;
	for(int i=0; i<w; i++){
		cin>>a[i]>>b[i]>>c[i];
		sa+=a[i];
	}
	for(int i=1; i<w; i++){
		x[i]=a[i]+a[i-1]+c[i];
	}
	if(w==1){
		cout<<0<<endl;
		return 0;
	}
	vector<P> v1, v2, v11;
	for(int i=0; i<(1<<(w/2)); i+=2){
		bool dame=0;
		for(int j=1; j<w/2; j++){
			if(i&(1<<j) && i&(1<<(j-1))){
				dame=1; break;
			}
		}
		if(dame) continue;
		ll xs=0, bs=0;
		for(int j=1; j<w/2; j++){
			if(i&(1<<j)){
				xs+=x[j], bs+=b[j];
			}
		}
		v1.push_back({xs, bs});
		if(!(i&(1<<(w/2-1)))) v11.push_back({xs, bs});
	}
	for(int i=0; i<(1<<(w-w/2)); i++){
		bool dame=0;
		for(int j=1; j<w-w/2; j++){
			if(i&(1<<j) && i&(1<<(j-1))){
				dame=1; break;
			}
		}
		if(dame) continue;
		ll xs=0, bs=0;
		for(int j=1; j<w-w/2; j++){
			if(i&(1<<j)){
				xs+=x[w/2+j], bs+=b[w/2+j];
			}
		}
		v2.push_back({xs, bs});
	}
	sort(v1.begin(), v1.end());
	sort(v11.begin(), v11.end());
	sort(v2.begin(), v2.end());
	/*for(int i=1; i<v1.size(); i++){
		v1[i].second=max(v1[i].second, v1[i-1].second);
	}
	for(int i=1; i<v11.size(); i++){
		v11[i].second=max(v11[i].second, v11[i-1].second);
	}*/
	for(int i=1; i<v2.size(); i++){
		v2[i].second=max(v2[i].second, v2[i-1].second);
	}
	ll ans=0;
	for(auto p:v1){
		if(p.first>sa) continue;
		int k=upper_bound(v2.begin(), v2.end(), P(sa-p.first, 1e18))-v2.begin();
		if(k==0) continue;
		ans=max(ans, p.second+v2[k-1].second);
	}
	for(auto p:v11){
		if(p.first>sa-x[w/2]) continue;
		int k=upper_bound(v2.begin(), v2.end(), P(sa-p.first-x[w/2], 1e18))-v2.begin();
		if(k==0) continue;
		ans=max(ans, p.second+v2[k-1].second+b[w/2]);
	}
	cout<<ans<<endl;
	return 0;
}