#include using namespace std; using lint = long long int; using pint = pair; using plint = pair; struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define ALL(x) (x).begin(), (x).end() #define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i=i##_begin_;i--) #define REP(i, n) FOR(i,0,n) #define IREP(i, n) IFOR(i,0,n) template bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; } template bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; } template istream &operator>>(istream &is, vector &vec){ for (auto &v : vec) is >> v; return is; } template ostream &operator<<(ostream &os, const vector &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; } #define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl; vector sol(vector v) { int n = v.size(); vector ret(4e6, plint(1e18, 1e18)); int t = 0; REP(S, 1 << n) { if (S & (S >> 1)) continue; lint cost = 0, val = 0; REP(d, n) if ((S >> d) & 1) cost += v[d].first, val += v[d].second; ret[t] = plint(cost, val); t++; } ret.resize(t); std::sort(ALL(ret)); IREP(i, t - 1) if (ret[i].first == ret[i + 1].first) ret[i] = ret[i + 1]; return ret; } lint maxcost; lint solve(vector v1, vector v2) { vector w1 = sol(v1); vector w2 = sol(v2); lint ret = 0; for (auto p : w1) { lint cost = maxcost - p.first; auto itr = lower_bound(ALL(w2), plint(cost + 1, -1)); if (itr == w2.begin()) continue; mmax(ret, prev(itr)->second + p.second); } return ret; } int main() { int W; cin >> W; if (W == 1) { puts("0"); return 0; } vector A(W), B(W), C(W); REP(i, W) cin >> A[i] >> B[i] >> C[i]; maxcost = accumulate(ALL(A), 0LL); int n = (W - 1) / 2; vector cost_v1, cost_v2; vector D; REP(i, W - 1) D.emplace_back(A[i] + A[i + 1] + C[i + 1], B[i + 1]); REP(i, n - 1) cost_v1.emplace_back(D[i]); FOR(i, n, W - 1) cost_v2.emplace_back(D[i]); lint ret1 = solve(cost_v1, cost_v2); cost_v1.clear(); cost_v2.clear(); REP(i, n) cost_v1.emplace_back(D[i]); FOR(i, n + 1, W - 1) cost_v2.emplace_back(D[i]); lint ret2 = solve(cost_v1, cost_v2); cout << max(ret1, ret2) << endl; }