#include #include #define llint long long #define inf 1e18 using namespace std; llint n; llint a[200005], sum[200005]; int main(void) { ios::sync_with_stdio(0); cin.tie(0); cin >> n; for(int i = 1; i <= n; i++) cin >> a[i], a[i] *= 2; sort(a+1, a+n+1); if(n <= 2){ cout << 0 << endl; return 0; } for(int i = 1; i <= n; i++) sum[i] = sum[i-1] + a[i]; llint ans = 0; for(llint i = 2; i <= n-1; i++){ llint m = a[i]; llint ub = min(n-i, i-1)+1, lb = 0, mid; while(ub-lb>1){ mid = (ub+lb)/2; if(a[n-mid+1] + a[i-mid] > 2*m) lb = mid; else ub = mid; } llint tmp = sum[n]-sum[n-lb] + sum[i]-sum[i-lb-1] - m*(2*lb+1); //cout << i << " " << m << " " << lb << " " << tmp << endl; ans = max(ans, tmp); } for(llint i = 2; i <= n-2; i++){ llint m = (a[i]+a[i+1])/2; llint ub = min(n-(i+1), i-1)+1, lb = 0, mid; while(ub-lb>1){ mid = (ub+lb)/2; if(a[n-mid+1] + a[i-mid] > 2*m) lb = mid; else ub = mid; } llint tmp = sum[n]-sum[n-lb] + sum[i+1]-sum[i-lb-1] - m*(2*lb+2); ans = max(ans, tmp); } cout << ans / 2 << endl; return 0; }