#include <iostream>
#include <vector>
#include <map>
#include <algorithm>
using namespace std;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

#define COUT(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << endl
template<class T1, class T2> ostream& operator << (ostream &s, pair<T1,T2> P)
{ return s << '<' << P.first << ", " << P.second << '>'; }
template<class T> ostream& operator << (ostream &s, vector<T> P)
{ for (int i = 0; i < P.size(); ++i) { if (i > 0) { s << " "; } s << P[i]; } return s; }
template<class T> ostream& operator << (ostream &s, vector<vector<T> > P)
{ for (int i = 0; i < P.size(); ++i) { s << endl << P[i]; } return s << endl; }

#define EACH(i, s) for (__typeof__((s).begin()) i = (s).begin(); i != (s).end(); ++i)
template<class T1, class T2> ostream& operator << (ostream &s, map<T1,T2> P)
{ EACH(it, P) { s << "<" << it->first << "->" << it->second << "> "; } return s << endl; }




using pll = pair<long long, long long>;
const long long INF = 1LL<<60;
int N;
vector<long long> a, b, c;

// 後半の各所持金差額に対する獲得好感度の差分ん最大値を求める
void rec(int n, int finish, map<long long, long long> &ma, long long syoji = 0, long long love = 0) {
    if (n == finish) {
        chmax(ma[-syoji], love);
        return;
    }

    // アルバイト
    rec(n + 1, finish, ma, syoji + a[n], love);

    // 学校からのデート
    if (n + 2 <= finish) rec(n + 2, finish, ma, syoji - c[n+1], love + b[n+1]);
}

long long solve(int mid) {
    map<long long, long long> former, latter;
    rec(0, mid, former);
    rec(mid, N, latter);
    long long cur = -INF;
    map<long long, long long> maxlatter;
    maxlatter[-INF] = -INF;
    for (auto it : latter) maxlatter[it.first] = max(cur, it.second);

    //COUT(former); COUT(latter); COUT(maxlatter);

    long long res = 0;
    for (auto it : former) {
        long long need = -(it.first);
        auto it2 = maxlatter.upper_bound(need);
        --it2;
        chmax(res, it.second + it2->second);

        //cout << pll(it.first, it.second) << ": " << pll(it2->first, it2->second) << endl;
    }
    return res;
}

int main() {
    while (cin >> N) {
    a.resize(N), b.resize(N), c.resize(N);
    for (int i = 0; i < N; ++i) cin >> a[i] >> b[i] >> c[i];
    cout << max(solve(N/2), solve(N/2+1)) << endl;
    }
}