#include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long int ll; typedef pair P; const int INF=1e9+10000; int n; int a[2000]; int b[2000]; int memo[2000][2000]; int solve(int i, int j){ if(i==j) return 0; if(memo[i][j]) return memo[i][j]; int ans=INF; if(i=0){ if(s1+j-i<=b[i]) ans=min(ans, s1+j-i); } int s2=solve(i+1, j); if(s2>=0){ if(s2+1<=b[i]) ans=min(ans, s2+1); } }else{ int s1=solve(j, i-1); if(s1>=0){ if(s1+i-j<=b[i]) ans=min(ans, s1+i-j); } int s2=solve(i-1, j); if(s2>=0){ if(s2+1<=b[i]) ans=min(ans, s2+1); } } if(ans==INF) return memo[i][j]=-1; else return memo[i][j]=ans; } int main() { cin>>n; int mx=0; for(int i=0; i>a[i]; mx=max(mx, a[i]); } int t1=mx, t2=mx+n; while(t1!=t2){ int t0=(t1+t2)/2; for(int i=0; i