#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; typedef unsigned int ui; const ll mod = 1000000007; const ll INF = (ll)1000000007 * 1000000007; typedef pair P; #define stop char nyaa;cin>>nyaa; #define rep(i,n) for(int i=0;i=0;i--) #define Rep(i,sta,n) for(int i=sta;i=sta;i--) #define rep1(i,n) for(int i=1;i<=n;i++) #define per1(i,n) for(int i=n;i>=1;i--) #define Rep1(i,sta,n) for(int i=sta;i<=n;i++) typedef long double ld; typedef complex Point; const ld eps = 1e-8; const ld pi = acos(-1.0); typedef pair LP; template struct SegmentTree{ using F = function; int n; F f;//二項演算 T ti;//単位元 vector dat; SegmentTree(){} SegmentTree(F f,T ti):f(f),ti(ti){} void init(int n_){//sizeがn_のsegtreeを作る n=1; while(n &v){//vによってsegtreeをbuildする int n_=v.size(); init(n_); for(int i=0;i>=1) dat[k]=f(dat[(k<<1)|0],dat[(k<<1)|1]); } T query(int a,int b){//区間[a,b)に対しFを適応した値を返す if(a>=b) return ti; T vl=ti,vr=ti; for(int l=a+n,r=b+n;l>=1,r>>=1) { if(l&1) vl=f(vl,dat[l++]); if(r&1) vr=f(dat[--r],vr); } return f(vl,vr); } template int find(int st,C &check,T &acc,int k,int l,int r){// if(l+1==r){ acc=f(acc,dat[k]); return check(acc)?k-n:-1; } int m=(l+r)>>1; if(m<=st) return find(st,check,acc,(k<<1)|1,m,r); if(st<=l&&!check(f(acc,dat[k]))){ acc=f(acc,dat[k]); return -1; } int vl=find(st,check,acc,(k<<1)|0,l,m); if(~vl) return vl; return find(st,check,acc,(k<<1)|1,m,r); } template int find(int st,C &check){ T acc=ti; return find(st,check,acc,1,0,n); } }; int n,a[200010],r[200010],l[200010]; string s[200010]; void solve(){ cin >> n; rep(i,n){ cin >> s[i]; } int M=0; rep(i,n-1){ a[i]=0; //cout << s[i] << endl; for(int k=0;k seg_l(f_max,0),seg_r(f_min,n); seg_l.init(M+1);seg_r.init(M+1); rep(i,n-1){ l[i]=seg_l.query(0,a[i]); seg_l.set_val(a[i],i+1); } per(i,n-1){ r[i]=seg_r.query(0,a[i]+1); seg_r.set_val(a[i],i+1); } ll ans=0; rep(i,n-1){ //cout << i << " " << l[i] << " " << r[i] << endl; ans+=(ll)a[i]*((ll)(i-l[i]+1)*(ll)(r[i]-2+i)*(ll)(r[i]-1-i)/2-(ll)(r[i]-i-1)*(ll)(i+l[i])*(ll)(i-l[i]+1)/2+2*(ll)(r[i]-i-1)*(ll)(i-l[i]+1)); //cout << ans << endl; } rep(i,n){ ans+=s[i].length(); } cout << ans << endl; } int main(){ ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(50); solve(); }