#include #include #include using namespace std; using ll = long long; constexpr int MOD = 1000000007; class mint { int n; public: mint(int n_ = 0) : n(n_) {} explicit operator int() { return n; } friend mint operator-(mint a) { return -a.n + MOD * (a.n != 0); } friend mint operator+(mint a, mint b) { int x = a.n + b.n; return x - (x >= MOD) * MOD; } friend mint operator-(mint a, mint b) { int x = a.n - b.n; return x + (x < 0) * MOD; } friend mint operator*(mint a, mint b) { return (long long)a.n * b.n % MOD; } friend mint &operator+=(mint &a, mint b) { return a = a + b; } friend mint &operator-=(mint &a, mint b) { return a = a - b; } friend mint &operator*=(mint &a, mint b) { return a = a * b; } friend bool operator==(mint a, mint b) { return a.n == b.n; } friend bool operator!=(mint a, mint b) { return a.n != b.n; } friend istream &operator>>(istream &i, mint &a) { return i >> a.n; } friend ostream &operator<<(ostream &o, mint a) { return o << a.n; } }; vector kakeru(vector a, vector b) { const int n = a.size(); const int m = b.size(); vector c(n + m - 1); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { c[i + j] += a[i] * b[j]; } } return c; } vector nizyou(vector a) { return kakeru(a, a); } // b[0] が 1 でないと正しく動かない。 vector waru(vector a, vector b, int n) { a.resize(n + 1); const int m = b.size(); vector c(n + 1); for (int i = 0; i <= n; i++) { c[i] = a[i]; for (int j = 0; j < m && i + j <= n; j++) { a[i + j] -= b[j] * c[i]; } } return c; } int main() { mint p; cin >> p; int Q; cin >> Q; // x^2f(x) = a[0] x^2 + a[1] x^3 + ... // px f(x) = pa[0]x + pa[1]x^2 + pa[2]x^3 + ... // f(x) = a[0] + a[1]x + a[2] x^2 + a[3]x^3 + ... // ------------------------------------------------------- // f(x) - px f(x) - x^2 f(x) = a[0] + a[1]*x + a[2]*x^2 - p*a[0]*x - p*a[1]*x^2 - a[0]*x^2 // = x^2 // f(x) = x^2 / (1 - px - x^2) // f(x)^2 = x^4 / (1 - px - x^2)^2 vector bunsi = {0, 0, 0, 0, 1}; vector bunbo = nizyou({1, -p, -mint(1)}); vector ans = waru(bunsi, bunbo, 2000000); for (int i = 0; i < Q; i++) { int q; cin >> q; cout << ans[q] << '\n'; } }