#include #define rep(i, a) for (int i = 0; i < (a); i++) #define rep2(i, a, b) for (int i = (a); i < (b); i++) #define repr(i, a) for (int i = (a) - 1; i >= 0; i--) #define repr2(i, a, b) for (int i = (b) - 1; i >= (a); i--) using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 9; ll dp1[205][2030][2]; // pos, sum, less ll dp2[205][2030][2]; // pos, sum, less void calc(ll dp[205][2030][2], string s) { dp[0][0][0] = 1; rep (i, s.length()) { rep (j, 2020) { rep (k, 2) { int ub; if (k) { ub = 9; } else { ub = s[i] - '0'; } rep (l, ub + 1) { (dp[i + 1][j + l][k || l < ub] += dp[i][j][k]) %= mod; } } } } } int main() { string M, D; cin >> M >> D; calc(dp1, M); calc(dp2, D); rep (j, 2020) { dp1[M.length()][j][0] += dp1[M.length()][j][1]; dp2[D.length()][j][0] += dp2[D.length()][j][1]; } ll ans = 0; rep2 (i, 1, 2020) { ans += dp1[M.length()][i][0] * dp2[D.length()][i][0]; ans %= mod; } cout << ans << endl; }