# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
#include <stdio.h>
#include<time.h>
#include <stdlib.h>
#include <cstdint>
#include <cfenv>
#include<fstream>
//#include <bits/stdc++.h>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
long long MOD = 1000000000 + 7;// 998244353;// ;
constexpr long long INF = numeric_limits<LL>::max() / 2;
const double PI = acos(-1);
#define fir first
#define sec second
#define thi third
#define debug(x) cerr<<#x<<": "<<x<<'\n'
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
struct Fll { LL first, second, third, fourd; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Rrep(i,mf) for(LL i=mf-1;i>=0;i--)
void YN(bool f) {
	if (f)
		cout << "YES" << endl;
	else
		cout << "NO" << endl;
}
void yn(bool f) {
	if (f)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
}
struct Edge { LL to, cost; };
struct edge { LL from, to, cost; };
vector<vector<LL>>g, rev;
vector<edge>edges;
vector<LL>v;
map<LL, LL>ma;
set<LL>st;
LL h, w, n, m, k, t, s, p, q, last, cnt, sum[210000], ans[210000], a[510000], b[510000], dp[310][310][310];
string str, ss;
bool f;
char c;
template<typename T>
class ConvexHullTrick {
private:
	// 直線群(配列)
	std::vector<std::pair<T, T>> lines;
	// 最小値(最大値)を求めるxが単調であるか
	bool isMonotonicX;
	// 最小/最大を判断する関数
	std::function<bool(T l, T r)> comp;

public:
	// コンストラクタ ( クエリが単調であった場合はflag = trueとする )
	ConvexHullTrick(bool flagX = false, std::function<bool(T l, T r)> compFunc = [](T l, T r) {return l >= r; })
		:isMonotonicX(flagX), comp(compFunc) {
		//lines.emplace_back(0, 0);//これいるかどうかはわからない
	};
	void clear() {
		lines.clear();
	}
	// 直線l1, l2, l3のうちl2が不必要であるかどうか
	bool check(std::pair<T, T> l1, std::pair<T, T> l2, std::pair<T, T> l3) {
		if (l1 < l3) std::swap(l1, l3);
		return (l3.second - l2.second) * (l2.first - l1.first) >= (l2.second - l1.second) * (l3.first - l2.first);
		//return comp((l3.second - l2.second) * (l2.first - l1.first), (l2.second - l1.second) * (l3.first - l2.first));
	}

	// 直線y=ax+bを追加する
	void add(T a, T b) {
		std::pair<T, T> line(a, b);
		while (lines.size() >= 2 && check(*(lines.end() - 2), lines.back(), line))
			lines.pop_back();
		lines.emplace_back(line);
	}

	// i番目の直線f_i(x)に対するxの時の値を返す
	T f(int i, T x) {
		return lines[i].first * x + lines[i].second;
	}

	// i番目の直線f_i(x)に対するxの時の値を返す
	T f(std::pair<T, T> line, T x) {
		return line.first * x + line.second;
	}

	// 直線群の中でxの時に最小(最大)となる値を返す
	T get(T x) {
		// 最小値(最大値)クエリにおけるxが単調
		if (isMonotonicX) {
			static int head = 0;
			while (lines.size() - head >= 2 && comp(f(head, x), f(head + 1, x)))
				++head;
			return f(head, x);
		}
		else {
			int low = -1, high = lines.size() - 1;
			while (high - low > 1) {
				int mid = (high + low) / 2;
				(comp(f(mid, x), f(mid + 1, x)) ? low : high) = mid;
			}
			return f(high, x);
		}
	}
};
//[L,R)
LL chmin[210000];
void dfs(LL L,LL R) {
	if (R-L<=2) {
		return;
	}
	ConvexHullTrick<LL> cht(n);
	LL mid = (L + R) / 2;
	for (int i =R; i > mid; i--) {
		cht.add(-2 * i, i * i + sum[i]);
	}
	chmin[L] = INF;
	for (int i = L; i <= mid;i++) {
		chmin[i] = min(chmin[i], cht.get(i) + i * i - sum[i]);
		chmin[i + 1] = chmin[i];
		ans[i] = min(ans[i], chmin[i]);
	}
	cht.clear();
	for (int i = L; i <=mid; i++) {
		cht.add(-2 * i, i * i - sum[i]);
	}
	chmin[R - 1] = INF;
	for (int i = R; i > mid; i--) {
		chmin[i - 1] = min(cht.get(i) + i * i + sum[i], chmin[i - 1]);
		chmin[i - 2] = chmin[i - 1];
		ans[i - 1] = min(ans[i - 1], chmin[i - 1]);
	}

	dfs(L, (L + R) / 2);
	dfs((L + R) / 2, R);
}
int main() {
	cin >> n;
	rep(i, n) {
		cin >> a[i];
		sum[i + 1] = sum[i] + a[i];
		ans[i] = a[i] + 1;
	}
	dfs(0,n);
	rep(i, n)
		cout << ans[i] << endl;
	return 0;
}