#include #define rep(i,n) for(int i = 0; i < (n); ++i) #define srep(i,s,t) for (int i = s; i < t; ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) using namespace std; typedef long long int ll; typedef pair P; #define yn {puts("Yes");}else{puts("No");} #define MAX_N 200005 int main() { int n, k; cin >> n >> k; string s; cin >> s; int a[n]; rep(i,n)a[i] = s[i] - '0'; int ans = 0; int now = 0; if(k < 1000000){ rep(i,k){ if(now > 0)now--; else ans++; now += a[i%n]; } }else{ rep(i,n){ if(now > 0)now--; else ans++; now += a[i%n]; } if(ans == 1 && now > 0){ cout << 1 << endl; return 0; } k -= n; if(now == 0){ ans += (k / n) * ans; k -= (k / n) * n; rep(i,k){ if(now > 0)now--; else ans++; now += a[i%n]; } cout << ans << endl; return 0; } int now2 = now; int cnt = 0; rep(i,n){ if(now > 0)now--; else cnt++; now += a[i%n]; } k -= n; ans += cnt; if(now == now2){ ans += (k / n) * cnt; k -= (k / n) * n; rep(i,k){ if(now > 0)now--; else ans++; now += a[i%n]; } cout << ans << endl; return 0; } } cout << ans << endl; return 0; }