#include <bits/stdc++.h>
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep1(i, n) for (ll i = 1; i <= (n); ++i)
#define rrep(i, n) for (ll i = (n - 1); i >= 0; --i)
#define ALL(obj) (obj).begin(), (obj).end()
#define pb push_back
#define to_s to_string
#define len(v) (int)v.size()
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define print(x) cout << (x) << '\n'
#define debug(x) cout << #x << ": " << (x) << '\n'
using namespace std;
using ll = long long;
typedef pair<ll, ll> P;
ll MOD = 1e9 + 7;
ll devc(ll x, ll y) { return 1 + (x - 1) / y; }

template <class T>
struct fenwick_tree
{
    int n;
    std::vector<T> x;
    fenwick_tree(int n_ = 0) : n(n_), x(n + 1, 0) {}
    int size() const { return n; }
    T sum(int r) const
    {
        T S = 0;
        for (r = r - 1; r >= 0; r = (r & (r + 1)) - 1)
            S += x[r];
        return S;
    }
    T sum(int l, int r) const { return sum(r) - sum(l); }
    void add(int k, const T &a)
    {
        for (; k < n; k |= k + 1)
            x[k] += a;
    }
    void set(int k, const T &a) { add(k, a - sum(k, k + 1)); }
};

template <class T>
struct fenwick_tree_range
{
    fenwick_tree<T> a, b;
    fenwick_tree_range(int n = 0) : a(n), b(n) {}
    int size() const { return a.size(); }
    T sum(int r) const { return a.sum(r) + b.sum(r) * r; }
    T sum(int l, int r) const { return sum(r) - sum(l); }
    void add(int r, const T &x)
    {
        a.add(r, x * r);
        b.add(r, -x);
    }
    void add(int l, int r, const T &x)
    {
        add(l, -x);
        add(r, x);
    }
};

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(0);
    cout << fixed << setprecision(20);

    ll N, Q;
    cin >> N >> Q;
    vector<ll> A(N);
    fenwick_tree<ll> B(N);

    rep(i, N) cin >> A[i];

    rep(i, Q){
        char c;
        ll x, y;
        cin >> c >> x >> y;
        --x;
        if(c == 'A') A[x] += y;
        else{
            --y;
            for (ll j = x; j <= y; ++j){
                B.add(j, A[j]);
            }
        }
    }

    rep(i,N){
        ll x = B.sum(i, i + 1);
        cout << x << " ";
    }


    return 0;
}