#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------


int N,Q;

template<class V, int ME> class BIT {
public:
	V bit[1<<ME];
	V operator()(int e) {if(e<0) return 0;V s=0;e++;while(e) s+=bit[e-1],e-=e&-e; return s;}
	void add(int e,V v) { e++; while(e<=1<<ME) bit[e-1]+=v,e+=e&-e;}
};
BIT<int,20> num;

ll A[202020];
string C[202020];
ll X[202020],Y[202020];
ll ret[202020];


void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>Q;
	FOR(i,N) cin>>A[i+1];
	FOR(i,Q) {
		cin>>C[i]>>X[i]>>Y[i];
	}
	for(i=Q-1;i>=0;i--) {
		if(C[i]=="A") {
			ret[X[i]]+=num(X[i])*Y[i];
		}
		else {
			Y[i]++;
			num.add(X[i],1);
			num.add(Y[i],-1);
		}
	}
	for(i=1;i<=N;i++) cout<<(ret[i]+A[i]*num(i))<<" ";
		
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}