#include <cstdio>
#include <iostream>
#include <string>
#include <sstream>
#include <stack>
#include <algorithm>
#include <cmath>
#include <queue>
#include <map>
#include <set>
#include <cstdlib>
#include <bitset>
#include <tuple>
#include <assert.h>
#include <deque>
#include <bitset>
#include <iomanip>
#include <limits>
#include <chrono>
#include <random>
#include <array>
#include <unordered_map>
#include <functional>
#include <complex>

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

const long long MAX = 5100000;
const long long INF = 1LL << 60;
const int inf = 1 << 28;
const long long mod = 1000000007LL;
//const long long mod = 998244353LL;

using namespace std;
typedef unsigned long long ull;
typedef long long ll;
template <typename T, typename E>
struct lazySegTree {
	using F = function<T(T, T)>;
	using G = function<T(T, E)>;
	using H = function<E(E, E)>;
	using P = function<E(E, int)>;
	F f; G g; H h; P p; T d1; E d0;
	int n;
	vector<T> dat;
	vector<E> lazy;

	lazySegTree() {}
	lazySegTree(int n_, F f_, G g_, H h_,
		T d1_, E d0_, P p_ = [](E a, int b) {return a; })
		: f(f_), g(g_), h(h_), p(p_), d1(d1_), d0(d0_)
	{
		n = 1; while (n < n_) n *= 2;
		dat.assign(n * 2 - 1, d1);
		lazy.assign(n * 2 - 1, d0);
	}
	void build(vector<T> v) {
		for (ll i = 0; i < v.size(); i++) dat[i + n - 1] = v[i];
		for (int i = n - 2; i >= 0; --i) dat[i] = f(dat[i * 2 + 1], dat[i * 2 + 2]);
	}

	// 区間の幅がlenの節点kについて遅延評価
	inline void eval(int len, int k) {
		if (lazy[k] == d0) return;
		if (k * 2 + 1 < n * 2 - 1) {
			lazy[2 * k + 1] = h(lazy[k * 2 + 1], lazy[k]);
			lazy[2 * k + 2] = h(lazy[k * 2 + 2], lazy[k]);
		}
		dat[k] = g(dat[k], p(lazy[k], len));
		lazy[k] = d0;
	}
	// [a, b)
	T update(int a, int b, E x, int k, int l, int r) {
		eval(r - l, k);
		if (b <= l || r <= a) return dat[k];
		if (a <= l && r <= b) {
			lazy[k] = h(lazy[k], x);
			return g(dat[k], p(lazy[k], r - l));
		}
		return dat[k] = f(update(a, b, x, 2 * k + 1, l, (l + r) / 2),
			update(a, b, x, 2 * k + 2, (l + r) / 2, r));
	}
	T update(int a, int b, E x) { return update(a, b, x, 0, 0, n); }
	// [a, b)
	T query(int a, int b, int k, int l, int r) {
		eval(r - l, k);
		if (a <= l && r <= b) return dat[k];
		bool left = !((l + r) / 2 <= a || b <= l), right = !(r <= 1 || b <= (l + r) / 2);
		if (left && right) return f(query(a, b, 2 * k + 1, l, (l + r) / 2), query(a, b, 2 * k + 2, (l + r) / 2, r));
		if (left) return query(a, b, 2 * k + 1, l, (l + r) / 2);
		return query(a, b, 2 * k + 2, (l + r) / 2, r);
	}
	T query(int a, int b) { return query(a, b, 0, 0, n); }

};

ll f(ll a, ll b) {
	return min(a, b);
}

ll g(ll a, ll b) {
	return a + b;
}
int main()
{
	/*
	cin.tie(nullptr);
	ios::sync_with_stdio(false);
	*/
	ll N, Q; scanf("%lld %lld", &N, &Q);
	vector<ll> a(N); for (ll i = 0; i < N; i++) scanf("%lld", &a[i]);
	vector<ll> b(N);
	lazySegTree<ll, ll> lsg(N + 1, f, g, g, 0LL, 0LL);
	while (Q--) {
		char c; cin >> c;
		if (c == 'A') {
			ll x, y; scanf("%lld %lld", &x, &y);
			x--;
			ll t = lsg.query(x, x + 1);
			b[x] += a[x] * t;
			lsg.update(x, x + 1, -t);
			a[x] += y;
		}
		else {
			ll x, y; scanf("%lld %lld", &x, &y);
			x--;
			lsg.update(x, y, 1);
		}
	}
	for (ll i = 0; i < N; i++) {
		b[i] += lsg.query(i, i + 1) * a[i];
		printf("%lld", b[i]);
		if (i == N - 1) puts("");
		else printf(" ");
	}

	return 0;
	/*
		おまじないを使ったらscanfとprintf関連注意！！！！！！！！！！！！
	*/
}