#include #include #include #include using namespace std; typedef long long ll; typedef pair P; typedef pair T; long long int INF = 1e18; const ll fact_table = 800008; double Pi = 3.1415926535897932384626; priority_queue pql; priority_queue

pqp; //big priority queue priority_queue ,greater > pqls; priority_queue ,greater

> pqps; //small priority queue //top pop ll dx[8]={1,0,-1,0,1,1,-1,-1}; ll dy[8]={0,1,0,-1,1,-1,-1,1}; char dir[] = "DRUL"; //↓,→,↑,← #define p(x) cout< number2){ swap(number1,number2); } if(number1 == 0 || number1 == number2){ return number2; }else{ return gcd(number2 % number1,number1); } } void YES(bool condition){ if(condition){ p("YES"); }else{ p("NO"); } return; } void Yes(bool condition){ if(condition){ p("Yes"); }else{ p("No"); } return; } /* ll fact[fact_table + 5],rfact[fact_table + 5]; void c3_init(){ fact[0] = rfact[0] = 1; for(ll i=1; i<=fact_table; i++){ fact[i] = (fact[i-1]*i) % mod; } rfact[fact_table] = rui(fact[fact_table],mod - 2); for(ll i=fact_table; i>=1; i--){ rfact[i-1] = rfact[i] * i; rfact[i-1] %= mod; } return;} ll c3(ll n,ll r){ return (((fact[n] * rfact[r]) % mod ) * rfact[n-r]) % mod;} */ bool multicase = false; ll n,m,num,sum,a,b,c,d,e,h,q; ll w, ans; ll k; ll x[2000005], y[2000005]; char s[5005], t[5005]; void calc(ll num){ if(num == 1){ x[1] = 1; return; } // iを素因数分解した結果を再起的に求める ll tmp = num; ll ans = 1; for(ll i=2;i*i<=tmp;i++){ ll cnt = 0; while(tmp % i == 0){ tmp /= i; cnt ++; } ans *= (cnt + 1); } if(tmp != 1)ans *= 2; x[num] = ans; return; } void solve(){ cin >> n; ll mid = n / 2; ll size = 1000; for(ll i=max(mid-size, 1ll);i<=min(n-1, mid+size);i++){ calc(i); } ll ans = INF; for(ll i=max(mid-size, 1ll);i<=min(n-1, mid+size);i++){ ll score1, score2; score1 = i - x[i]; score2 = n - i - x[n - i]; ans = min(ans, abs(score1 - score2)); y[i] = abs(score1 - score2); } for(ll i=max(mid-size, 1ll);i<=min(n-1, mid+size);i++){ if(y[i] == ans){ pe(i);p(n-i); } } return; } int main(){ // init(); //ios::sync_with_stdio(false); // cin.tie(nullptr); ll q; if(multicase){ cin >> q; }else{ q = 1; } while(q--){ solve(); } return 0; }