#include #define rep(i, a) for (int i = 0; i < (a); i++) #define rep2(i, a, b) for (int i = (a); i < (b); i++) #define repr(i, a) for (int i = (a) - 1; i >= 0; i--) #define repr2(i, a, b) for (int i = (b) - 1; i >= (a); i--) using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; double P[7]; double dp[1010101]; double E(int n) { if (n <= 0) return 0; if (dp[n] >= 0) return dp[n]; double res = 0; for (int i = 1; i <= 6; i++) { res += P[i] * (E(n - i) + 1); } return dp[n] = res; } int main() { int T; cin >> T; rep (i, 1010101) dp[i] = -1; dp[1] = 1.0000000000000000; dp[2] = 1.0833333333333333; dp[3] = 1.2569444444444444; dp[4] = 1.5353009259259260; dp[5] = 1.6915991512345676; dp[6] = 2.0513639724794235; P[1] = (dp[2] - 1) / dp[1]; P[2] = (dp[3] - P[1] * dp[2] - 1) / dp[1]; P[3] = (dp[4] - P[1] * dp[3] - P[2] * dp[2] - 1) / dp[1]; P[4] = (dp[5] - P[1] * dp[4] - P[2] * dp[3] - P[3] * dp[2] - 1) / dp[1]; P[5] = (dp[6] - P[1] * dp[5] - P[2] * dp[4] - P[3] * dp[3] - P[4] * dp[2] - 1) / dp[1]; P[6] = 1 - P[1] - P[2] - P[3] - P[4] - P[5]; while (T--) { int N; cin >> N; printf("%.20f\n", E(N)); } return 0; }