#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) REP(i,0,n)
#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)
#define repr(i, n) REPR(i, n, 0)
#define REPR(i, s, e) for(int i=(int)(s-1); i>=(int)(e); i--)
#define pb push_back
#define all(r) r.begin(),r.end()
#define rall(r) r.rbegin(),r.rend()
#define fi first
#define se second

typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const ll INF = 1e18;
const ll MOD = 1e9 + 7;
const double EPS = 1e-8;

template<typename T> T chmax(T& a, const T& b){return a = (a > b ? a : b);}
template<typename T> T chmin(T& a, const T& b){return a = (a < b ? a : b);}

using Int = __int128_t;
// https://kenkoooo.hatenablog.com/entry/2016/11/30/163533
std::ostream &operator<<(std::ostream &dest, __int128_t value) {
  std::ostream::sentry s(dest);
  if (s) {
    __uint128_t tmp = value < 0 ? -value : value;
    char buffer[128];
    char *d = std::end(buffer);
    do {
      --d;
      *d = "0123456789"[tmp % 10];
      tmp /= 10;
    } while (tmp != 0);
    if (value < 0) {
      --d;
      *d = '-';
    }
    int len = std::end(buffer) - d;
    if (dest.rdbuf()->sputn(d, len) != len) {
      dest.setstate(std::ios_base::badbit);
    }
  }
  return dest;
}
__int128 parse(string &s) {
  __int128 ret = 0;
  for (int i = 0; i < (int)s.length(); i++)
    if ('0' <= s[i] && s[i] <= '9')
      ret = 10 * ret + s[i] - '0';
  return ret;
}

int main(){
    Int a, b, h;
    {
        int _a, _b, _h;
        cin >> _a >> _b >> _h;
        a = _a;
        b = _b;
        h = _h;
    }
    a *= 1000;
    b *= 1000;

    auto check = [&](Int m, Int a, Int b, Int h) {
        rep(i, m) {
            if(a > b) swap(a, b);
            if(b <= h) return false;
            if(a <= h) swap(a, b);
            b *= 2;
            h *= 4;
        }
        return true;
    };
    
    Int l = 0, r = 32;
    rep(i, 128) {
        auto m = (l + r) / 2;
        if(check(m, a, b, h)) l = m;
        else r = m;
    }
    cout << l << endl;
    return 0;
}