#include typedef long long ll; using namespace std; int main(void) { // A * 60 * X >= C * 60 * 60 + B * X // (A * 60 - B) * X >= 3600 * C ll A,B,C; cin>>A>>B>>C; ll X; if (A * 60 - B > 0) { X = (3600 * C % (A * 60 - B) != 0) ? 3600 * C / (A * 60 - B) + 1 : 3600 * C / (A * 60 - B); cout << X << endl; } else { cout << "-1" << endl; } return 0; }