#pragma GCC target ("avx") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = int_fast64_t; using ld = long double; #define int ll #define all(a) (a).begin(),(a).end() #define fs first #define sc second #define xx first #define yy second.first #define zz second.second #define H pair #define P pair> #define Q(i,j,k) mkp(i,mkp(j,k)) #define R pair, pair> #define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l)) #define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++) #define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++) #define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--) #define range(i,v) for(auto& (i) : v) #define mkp make_pair #define mem(x,k) memset(x,k,sizeof(x)) #define vec vector #define pb emplace_back #define lb lower_bound #define ub upper_bound #define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end()) #define getidx(b,i) lower_bound(all(b),(i))-b.begin() #define ssp(i,n) (i==n-1?"\n":" ") #define ctoi(c) (int)(c-'0') #define itoc(c) (char)(c+'0') #define itn int #define pri_que priority_queue #define pp(x,y) pb(H{x,y}) #define ppp(x,y,z) pb(Q(x,y,z)) #define pppp(x,y,z,w) pb(S(x,y,z,w)) #define cyes cout<<"Yes\n" #define cno cout<<"No\n" //#define endl "\n" constexpr int mod = 1e9 + 7; constexpr int Mod = 998244353; constexpr int MXN = 500000 + 100; constexpr ld EPS = 1e-10; constexpr ll inf = 3 * 1e18; constexpr int Inf = 15 * 1e8; const vecdx{ -1,1,0,0 }, dy{ 0,0,-1,1 }; templatebool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; } templatebool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; } ll read() { ll u, k = scanf("%lld", &u); return u; } string reads() { string s; cin >> s; return s; } H readh(bool g = 0) { H u; ll k = scanf("%lld %lld", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; } void printh(H t) { printf("%lld %lld\n", t.fs, t.sc); } bool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; } ll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; } ll mod_pow(ll x, ll n, ll p = mod) { ll res = 1; while (n > 0) { if (n & 1) res = res * x % p; x = x * x % p; n >>= 1; } return res; }//x^n%p ll bitcount(ll x) { int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++; return sum; } /*constexpr int fn_ = 1000005; ll fact_[fn_], comp_[fn_]; ll comb(ll x, ll y, ll Mod = mod) { if (!fact_[0]) { fact_[0] = 1; comp_[0] = 1; for (int i = 1; i < fn_; i++) fact_[i] = fact_[i - 1] * i % Mod; comp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod); for (int i = fn_ - 2; i > 0; i--) comp_[i] = comp_[i + 1] * (i + 1) % Mod; } if (x < y) return 0; return fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod; }*/ //-------------------------------------------------------------- int n; int a[2000][2000]; int b[2000];//現在のコスト int ans[2000];//答えのコスト int c[2000][2]; mt19937 rnd(114514); void generate(int t) { string k = (t <= 9 ? "0" : ""); ofstream ifs("input/" + k + to_string(t) + ".txt"); n = rnd() % 1000 + 1; if (t <= 7) n %= 50 + 1; if (t == 2) n = 2; if (t == 1) n = 1; if (t >= 17) n = 1000; else if (t >= 15) n = 998; priority_queuep; rep(i, n)rep(j, n) p.push(H{ rnd(), i }); rep(i, n)rep(j, n) { a[i][j] = p.top().sc; p.pop(); } rep(i, n) { b[i] = 0; ans[i] = 0; c[i][0] = 0; c[i][1] = 0; } ifs << n << endl; rep(i, n)rep(j, n) { if (j == n - 1) ifs << a[i][j] + 1 << endl; else ifs << a[i][j] + 1 << " "; } } int solve2() { cin >> n; rep(i, n)rep(j, n) a[i][j] = read() - 1; int ans = 0; rep(i, n) { int res = inf; rep(j, n) { int sum = 0; //色iの視点をjにする rep(x, n)rep(y, n) { if (a[x][y] == i) { sum += abs(x - j) + y - min(abs(x - j), y); } } res = min(res, sum); } ans += res; } return ans; } int solve() { //cin >> n; rep(i, n)rep(j, n) { //a[i][j] = read() - 1; b[a[i][j]] += i + j - min(i, j); if (j < i) c[a[i][j]][1]++; } rep(i, n) { ans[i] = b[i]; } rep(i, n) { for (int j = 0; i - j >= 0; j++) { c[a[i - j][j]][0]++; } rep(j, n) { b[j] += c[j][0] - c[j][1]; } rep(j, n) chmin(ans[j], b[j]); for (int j = 0; i + j + 1 < n; j++) { c[a[i + j + 1][j]][1]--; } } int sum = 0; rep(i, n) sum += ans[i]; return sum; } signed main() { cout << solve2() << endl; /*rep(_, 20) { generate(_ + 1); string k = (_ <= 8 ? "0" : ""); ofstream ofs("output/" + k + to_string(_ + 1) + ".txt"); ofs << solve() << endl; ofs.close(); cout << _ << endl; }*/ }