#include <iostream>
#include <algorithm>
#include <utility>
#include <vector>
#include <numeric>
#include <tuple>

template <class T, class U>
inline bool chmin(T &lhs, const U &rhs) {
  if (lhs > rhs) {
    lhs = rhs;
    return true;
  }
  return false;
}

template <class T, class U>
inline bool chmax(T &lhs, const U &rhs) {
  if (lhs < rhs) {
    lhs = rhs;
    return true;
  }
  return false;
}

// [l, r) from l to r
struct range {
  struct itr {
    int i;
    constexpr itr(int i_): i(i_) { }
    constexpr void operator ++ () { ++i; }
    constexpr int operator * () const { return i; }
    constexpr bool operator != (itr x) const { return i != x.i; }
  };
  const itr l, r;
  constexpr range(int l_, int r_): l(l_), r(std::max(l_, r_)) { }
  constexpr itr begin() const { return l; }
  constexpr itr end() const { return r; }
};

// [l, r) from r to l
struct revrange {
  struct itr {
    int i;
    constexpr itr(int i_): i(i_) { }
    constexpr void operator ++ () { --i; }
    constexpr int operator * () const { return i; }
    constexpr bool operator != (itr x) const { return i != x.i; }
  };
  const itr r, l;
  constexpr revrange(int l_, int r_): l(l_ - 1), r(std::max(l_, r_) - 1) { }
  constexpr itr begin() const { return r; }
  constexpr itr end() const { return l; }
};

int main() {
  int N;
  long long X, Y, Z;
  std::cin >> N >> X >> Y >> Z;
  std::vector<long long> A(N);
  for (long long &x: A) {
    std::cin >> x;
    x = x / 1000 + 1;
  }
  for (long long &x: A) {
    long long t = x / 10;
    if (Z >= t) {
      x -= t * 10;
      Z -= t;
    }
    else {
      x -= Z * 10;
      Z = 0;
    }
    t = x / 5;
    if (Y >= t) {
      x -= t * 5;
      Y -= t;
    }
    else {
      x -= Y * 5;
      Y = 0;
    }
  }
  std::sort(A.rbegin(), A.rend());
  for (long long &x: A) {
    if (Z > 0) {
      --Z;
      x = 0;
    }
    else if (Y > 0) {
      --Y;
      x = 0;
    }
  }
  long long need = std::accumulate(A.cbegin(), A.cend(), 0ll);
  std::cout << (X + Y + Z >= need ? "Yes" : "No") << '\n';
  return 0;
}