#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <queue>
#include <string>
#include <map>
#include <set>
#include <stack>
#include <tuple>
#include <deque>
#include <numeric>
#include <bitset>
#include <iomanip>
#include <cassert>
#include <chrono>
#include <random>
#include <limits>
#include <iterator>
#include <functional>
#include <sstream>
#include <complex>
using namespace std;

typedef long long ll;
typedef uint64_t ull;
typedef pair<int, int> P;
typedef pair<int, double> Pid;
typedef pair<double, int> Pdi;
typedef pair<ll, int> Pl;
typedef pair<ll, ll> Pll;
typedef pair<int, pair<int, int>> PP;
typedef pair<P, int> PPi;
constexpr double PI = 3.1415926535897932;   // acos(-1)
constexpr double EPS = 1e-9;
constexpr int INF = 1001001001;
constexpr int mod = 1000000007;
// constexpr int mod = 998244353;

#define chmax(x, y) x = max(x, y)
#define chmin(x, y) x = min(x, y)
#define chadd(x, y) x = (x + y) % mod

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int n;
    int x, y, z;
    cin >> n >> x >> y >> z;
    vector<int> a(n);
    for(int i = 0; i < n; ++i)  cin >> a[i];
    sort(a.begin(), a.end(), greater<int>());
    for(int i = 0; i < n; ++i){
        int need = a[i] / 10000;
        if(need <= z){
            a[i] -= need * 10000;
            z -= need;
        }
        need = a[i] / 5000;
        if(need <= y){
            a[i] -= need * 5000;
            y -= need;
        }
        need = a[i] / 1000;
        if(need <= x){
            a[i] -= need * 1000;
            x -= need;
        }
    }

    sort(a.begin(), a.end());
    for(int i = 0; i < n; ++i){
        if(a[i] == 0){
            if(x > 0){
                --x;
                continue;
            }
            if(y > 0){
                --y;
                continue;
            }
            if(z > 0){
                --z;
                continue;
            }
        }
        else{
            int need = ceil((double)a[i] / 1000);
            if(need <= x){
                x -= need;
                continue;
            }
            need = ceil((double)a[i] / 5000);
            if(need <= y){
                y -= need;
                continue;
            }
            need = ceil((double)a[i] / 10000);
            if(need <= z){
                z -= need;
                continue;
            }
        }
        
        cout << "No\n";
        return 0;
    }

    cout << "Yes\n";
}