#pragma region Tmpl #include // clang-format off #define pb push_back #define eb emplace_back #define fi first #define se second #define each(x,v) for(auto& x : v) #define all(v) (v).begin(),(v).end() #define sz(v) ((int)(v).size()) #define ini(...) int __VA_ARGS__; in(__VA_ARGS__) #define inl(...) long long __VA_ARGS__; in(__VA_ARGS__) #define ins(...) string __VA_ARGS__; in(__VA_ARGS__) #define inc(...) char __VA_ARGS__; in(__VA_ARGS__) #define in2(s,t) rep(i,sz(s)){in(s[i] , t[i]);} #define in3(s,t,u) rep(i,sz(s)){in(s[i] , t[i] , u[i]);} #define in4(s,t,u,v) rep(i,sz(s)){in(s[i] , t[i] , u[i] , v[i]);} #ifdef ONLINE_JUDGE #define rep(i,N) for(int i = 0; i < (int)(N); i++) #define repr(i,N) for(int i = (int)(N) - 1; i >= 0; i--) #define rep1(i,N) for(int i = 1; i <= (int)(N) ; i++) #define repr1(i,N) for(int i = (N) ; (int)(i) > 0 ; i--) #else #define rep(i,N) for(long long i = 0; i < (long long)(N); i++) #define repr(i,N) for(long long i = (long long)(N) - 1; i >= 0; i--) #define rep1(i,N) for(long long i = 1; i <= (long long)(N) ; i++) #define repr1(i,N) for(long long i = (N) ; (long long)(i) > 0 ; i--) #endif using namespace std; void solve(); using ll = long long; template using V = vector; using vi = V; using vl = V<>; using vvi = V< V >; using vd = V; using vs = V; using vvl = V< V<> >; constexpr int inf = 1001001001; constexpr ll infLL = (1LL << 61) - 1; template inline bool amin(T &x, U y) { return (y < x) ? (x = y, true) : false; } template inline bool amax(T &x, U y) { return (x < y) ? (x = y, true) : false; } templatell ceil(T a,U b){return (a + b - 1) / b;} template ostream& operator <<(ostream& os, const pair &p) { os << p.first << " " << p.second; return os; } template istream& operator >>(istream& is, pair &p) { is >> p.first >> p.second; return is; } template ostream& operator <<(ostream& os, const vector &v) { int s = (int)v.size(); for(int i=0;i istream& operator >>(istream& is, vector &v) { for(auto &x : v) is >> x; return is; } void in(){} template void in(T &t,U &...u){ cin >> t; in(u...);} void out(){cout << "\n";} template void out(const T &t,const U &...u){ cout << t; if(sizeof...(u)) cout << " "; out(u...);} templatevoid die(T x){out(x); exit(0);} #ifdef NyaanDebug #include "NyaanDebug.h" #define trc(...) do { cerr << #__VA_ARGS__ << " = "; dbg_out(__VA_ARGS__);} while(0) #define trca(v,N) do { cerr << #v << " = "; array_out(v , N);} while(0) #define trcc(v) do { cerr << "name : " << #v << "\n"; int cnt = 0; each(x , v){cerr << (cnt++) << " : "; trc(x); } } while(0) #else #define trc(...) #define trca(...) #define trcc(...) int main(){solve();} #endif constexpr ll TEN(int n){ll ret=1,x=10;while(n){if(n&1)ret*=x;x*=x;n>>=1;}return ret;} #define mem(a, val) memset(a, val, sizeof(a)) #pragma endregion struct IoSetupNya {IoSetupNya() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); cerr << fixed << setprecision(7);} } iosetupnya; using P = pair; using vp = V

; constexpr uint32_t MOD = /** 1000000007; //*/ 998244353; // clang-format on //////////////////////////////////////////////////// vector> RunLengthEncoding(string& S){ vector> ret; char c = -1; int n = 0; for(char x : S){ if(c == x) n++; else{ if(n) ret.emplace_back(c , n); c = x , n = 1; } } if(n) ret.emplace_back(c , n); return ret; } template vector> RunLengthEncoding(vector& S){ vector> ret; T c = -1; int n = 0; for(T& x : S){ if(c == x) n++; else{ if(n) ret.emplace_back(c , n); c = x , n = 1; } } if(n) ret.emplace_back(c , n); return ret; } void q(){ ini(N); ins(S); rep(i,N-2){ if(S[i]=='o'&&S[i+1]=='o'&&S[i+2]=='o'){ out('O'); return; } if(S[i]=='-'&&S[i+1]=='o'&&S[i+2]=='o'){ out('O'); return; } if(S[i]=='o'&&S[i+1]=='-'&&S[i+2]=='o'){ out('O'); return; } if(S[i]=='o'&&S[i+1]=='o'&&S[i+2]=='-'){ out('O'); return; } } auto run = RunLengthEncoding(S); rep(i,sz(run)){ if(run[i].first == 'x') continue; if(run[i].first == '-'){ if(i == 0 || i == sz(run) - 1) continue; if(run[i-1].first == 'o' && run[i+1].first == 'o' && run[i].second % 2 == 1 ){ out('O'); return; } } if(run[i].first == 'o'){ if(i == 0 || i == sz(run) - 1) continue; if(run[i-1].first == '-' && run[i+1].first == '-' && run[i-1].second + run[i+1].second >= 3 ){ out('O'); return; } } } out('X'); } void solve(){ int T; cin >> T; for(int i = 0 ; i < T ; i++) q(); }