#include typedef long long ll; using namespace std; const int INF = 1e9; const int MOD = 1e9+7; const ll LINF = 1e18; #define FOR(i,a,b) for(int i=(a);i<(b);++i) #define REP(i,n) for(int i=0;i<(n);++i) #define REPR(i,n) for(int i=n;i>=0;i--) #define ALL(v) (v.begin(),v.end()) #define COUT(x) cout<<(x)<<'\n' int main(){ int n; cin >> n; queue q; vector vec(n+10,INF);//最小値を今回は求めるためINFで初期化 int now = 1; q.push(1);vec[1]=1; //最小経路を求めたいので幅優先選択を行う while(!q.empty()){//すべての転移がおわるまで now = q.front();q.pop(); int bit = __builtin_popcount(now); if(now-bit>0&&vec[now-bit]==INF){ vec[now-bit] = vec[now] + 1; q.push(now-bit); } if(now+bit<=n&&vec[now+bit]==INF){ vec[now+bit] = vec[now] + 1; q.push(now+bit); } } cout<<(vec[n]