#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
using namespace std;
#define FOR(i,m,n) for(int i=(m);i<(n);++i)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(),(v).end()
using ll = long long;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3f3fLL;
const double EPS = 1e-8;
const int MOD = 1000000007;
// const int MOD = 998244353;
const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};
const int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};
template <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }
template <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }
struct IOSetup {
  IOSetup() {
    cin.tie(nullptr);
    ios_base::sync_with_stdio(false);
    cout << fixed << setprecision(20);
  }
} iosetup;

template <typename Abelian>
struct BITRangeAdd {
  BITRangeAdd(int n_, const Abelian UNITY = 0) : n(n_), UNITY(UNITY) {
    ++n;
    dat_const.assign(n, UNITY);
    dat_linear.assign(n, UNITY);
  }

  void add(int left, int right, Abelian val) {
    if (right < ++left) return;
    for (int i = left; i < n; i += i & -i) {
      dat_const[i] -= val * (left - 1);
      dat_linear[i] += val;
    }
    for (int i = right + 1; i < n; i += i & -i) {
      dat_const[i] += val * right;
      dat_linear[i] -= val;
    }
  }

  Abelian sum(int idx) {
    Abelian res = UNITY;
    for (int i = idx; i > 0; i -= i & -i) res += dat_linear[i];
    res *= idx;
    for (int i = idx; i > 0; i -= i & -i) res += dat_const[i];
    return res;
  }

  Abelian sum(int left, int right) {
    if (right <= left) return UNITY;
    return sum(right) - sum(left);
  }

  Abelian operator[](const int idx) { return sum(idx, idx + 1); }

private:
  int n;
  const Abelian UNITY;
  vector<Abelian> dat_const, dat_linear;
};

int main() {
  int n; cin >> n;
  vector<vector<int>> a(n, vector<int>(n)); REP(i, n) REP(j, n) cin >> a[i][j], --a[i][j];
  vector<BITRangeAdd<ll>> bit(n, n);
  REP(i, n) REP(j, n) {
    int l = max(i - j, 0), r = min(i + j, n - 1);
    bit[a[i][j]].add(0, 1, j + l);
    bit[a[i][j]].add(1, l + 1, -1);
    bit[a[i][j]].add(r + 1, n, 1);
  }
  ll ans = 0;
  REP(i, n) {
    vector<ll> now(n);
    REP(j, n) now[j] = bit[i][j];
    FOR(j, 1, n) now[j] += now[j - 1];
    // REP(j, n) cout << now[j] << " \n"[j + 1 == n];
    ans += *min_element(ALL(now));
  }
  cout << ans << '\n';
  return 0;
}