#include #define rep(i, n) for (int i = 0; i < n; ++i) using ll = long long; using namespace std; const int INF = 1e9; int main() { int k; cin >> k; int cnt[210] = {0}; int a[] = {2, 3, 5, 7, 11, 13}; int b[] = {4, 6, 8, 9, 10, 12}; int sum = 0; rep(i, 6) rep(j, 6) { ++cnt[a[i] * b[j]]; } printf("%.13f\n", cnt[k] / 36.0); return 0; }