from itertools import permutations
import sys

sys.setrecursionlimit(10 ** 6)
from bisect import *
from collections import *
from heapq import *

def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split()))
def SI(): return sys.stdin.readline()[:-1]
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
int1 = lambda x: int(x) - 1
def MI1(): return map(int1, sys.stdin.readline().split())
def LI1(): return list(map(int1, sys.stdin.readline().split()))
p2D = lambda x: print(*x, sep="\n")
dij = [(1, 0), (0, 1), (-1, 0), (0, -1)]

def main():
    def dfs(u=0,pu=-1):
        uu.append(u)
        for v,_ in to[u]:
            if v==pu:continue
            dfs(v,u)

    inf=10**9
    n,m=MI()
    ss=[II() for _ in range(n)]
    to=[[] for _ in range(n)]
    dist=[[inf]*n for _ in range(n)]
    for u in range(n):dist[u][u]=0
    for _ in range(n-1):
        a,b,c=MI()
        to[a].append((b,c))
        to[b].append((a,c))
        dist[a][b]=dist[b][a]=c
    # ワーシャルフロイドで村と村の所要時間を計算
    for j in range(n):
        for i in range(n):
            for k in range(n):
                dist[i][k]=min(dist[i][k],dist[i][j]+dist[j][k])
    #p2D(dist)
    # dfsで訪問順を決める
    uu=[]
    dfs()
    #print(uu)
    # dp[j][k]...最後に訪ねた村のインデックスがjで、そこまでの時間がkの場合の最大金額
    dp=[[-inf]*(m+1) for _ in range(n)]
    dp[0][0]=ss[0]
    for i,u in enumerate(uu[1:],1):
        s=ss[u]
        for j in range(i-1,-1,-1):
            v=uu[j]
            d=dist[u][v]
            for k in range(m-d,-1,-1):
                pre = dp[j][k]
                if pre == -inf: continue
                dp[i][k+d]=max(dp[i][k+d],pre+s)
    ans=ss[0]
    dist0=dist[0]
    #p2D(dp)
    for i in range(1,n):
        u=uu[i]
        cur=-1
        if m-dist0[u]+1>0:cur=max(dp[i][:m-dist0[u]+1])
        if cur>ans:ans=cur
    print(ans)

main()