#include #define rep(i,a,b) for(int i=a;i=b;i--) #define fore(i,a) for(auto &i:a) #define all(x) (x).begin(),(x).end() //#pragma GCC optimize ("-O3") using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); } typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60; templatebool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; } templatebool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; } //--------------------------------------------------------------------------------------------------- /*---------------------------------------------------------------------------------------------------             ∧_∧       ∧_∧  (´<_` )  Welcome to My Coding Space!      ( ´_ゝ`) /  ⌒i @hamayanhamayan0     /   \    | |     /   / ̄ ̄ ̄ ̄/  |   __(__ニつ/  _/ .| .|____      \/____/ (u ⊃ ---------------------------------------------------------------------------------------------------*/ int N, I, J; //--------------------------------------------------------------------------------------------------- ll solve() { cin >> N >> I >> J; int mi = min({ I, J, N - 1 - I, N - 1 - J }); ll ans = 1LL * (N - 1 + N - 1 - (mi - 1) * 2) * mi / 2 * 4; I -= mi; J -= mi; N -= mi * 2; if (N == 1) return ans; else if (N == 2) { if (I == 0 && J == 0) return ans; else if (I == 0 && J == 1) return ans + 1; else if (I == 1 && J == 1) return ans + 2; return ans + 3; } else { if (I == 0) return ans + J; ans += N - 1; if (J == N - 1) return ans + I; ans += N - 1; if (I == N - 1) return ans + N - 1 - J; ans += N - 1; return ans + N - 1 - I; } } //--------------------------------------------------------------------------------------------------- void _main() { int Q; cin >> Q; rep(q, 0, Q) printf("%lld\n", solve()); }