/* このコード、と~おれ! Be accepted! ∧_∧  (。・ω・。)つ━☆・*。 ⊂   ノ    ・゜+.  しーJ   °。+ *´¨)          .· ´¸.·*´¨) ¸.·*¨)           (¸.·´ (¸.·'* ☆ */ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include /*多倍長整数/cpp_intで宣言 #include using namespace boost::multiprecision; */ //#pragma gcc target ("avx2") //#pragma gcc optimization ("o3") //#pragma gcc optimization ("unroll-loops") #define rep(i, n) for(int i = 0; i < (n); ++i) #define rep1(i, n) for(int i = 1; i <= (n); ++i) #define rep2(i, n) for(int i = 2; i < (n); ++i) #define repr(i, n) for(int i = n; i >= 0; --i) #define reprm(i, n) for(int i = n - 1; i >= 0; --i) #define printynl(a) printf(a ? "yes\n" : "no\n") #define printyn(a) printf(a ? "Yes\n" : "No\n") #define printYN(a) printf(a ? "YES\n" : "NO\n") #define printim(a) printf(a ? "possible\n" : "imposible\n") #define printdb(a) printf("%.50lf\n", a) //少数出力 #define printLdb(a) printf("%.50Lf\n", a) //少数出力 #define printdbd(a) printf("%.16lf\n", a) //少数出力(桁少なめ) #define prints(s) printf("%s\n", s.c_str()) //string出力 #define all(x) (x).begin(), (x).end() #define allsum(a, b, c) ((a + b) * c / 2LL) //等差数列の和、初項,末項,項数 #define pb push_back #define rpriq priq, greater> #define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI) #define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L) #define Please return #define AC 0 #define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d)) /*(a, b) から (c, d) のマンハッタン距離 */ using ll = long long; constexpr int INF = 1073741823; constexpr int MINF = -1073741823; constexpr ll LINF = ll(4661686018427387903); constexpr ll MOD = 1000000007; const long double PI = acosl(-1.0L); using namespace std; void scans(string& str) { char c; str = ""; scanf("%c", &c); if (c == '\n')scanf("%c", &c); while (c != '\n' && c != -1 && c != ' ') { str += c; scanf("%c", &c); } } void scanc(char& str) { char c; scanf("%c", &c); if (c == -1)return; while (c == '\n') { scanf("%c", &c); } str = c; } double acot(double x) { return PI / 2 - atan(x); } ll LSB(ll n) { return (n & (-n)); } /*-----------------------------------------ここからコード-----------------------------------------*/ void dfs(const vector>& tree, vector>>& a, const int& now, const int& bef, const int& cnt, const int& root) { a[root][cnt].emplace_back(now); for (const auto& aa : tree[now]) { if (aa != bef)dfs(tree, a, aa, now, cnt + 1, root); } } int main() { int n, q; scanf("%d%d", &n, &q); vector> tree(n); int a, b; rep(i, n - 1) { scanf("%d%d", &a, &b); --a; --b; tree[a].push_back(b); tree[b].push_back(a); } vector>> p(n, vector>(n)); rep(i, n) dfs(tree, p, i, -1, 0, i); vector ans(n); int x, y, z; rep(i, q) { scanf("%d%d%d", &x, &y, &z); printf("%d\n", ans[--x]); for (int j = 0; j <= y; ++j) { for (const auto& aa : p[x][j]) { ans[aa] += z; } } } Please AC; }