#include const long long INF = 1LL << 60; const long long MOD = 1000000007; const double PI = acos(-1.0); #define rep(i, n) for (ll i = 0; i < (n); ++i) #define rep1(i, n) for (ll i = 1; i <= (n); ++i) #define rrep(i, n) for (ll i = (n - 1); i >= 0; --i) #define perm(c) sort(ALL(c));for(bool c##p=1;c##p;c##p=next_permutation(ALL(c))) #define ALL(obj) (obj).begin(), (obj).end() #define RALL(obj) (obj).rbegin(), (obj).rend() #define pb push_back #define to_s to_string #define len(v) (ll)v.size() #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define print(x) cout << (x) << '\n' #define drop(x) cout << (x) << '\n', exit(0) #define debug(x) cout << #x << ": " << (x) << '\n' using namespace std; using ll = long long; typedef pair P; typedef vector vec; typedef vector> vec2; typedef vector>> vec3; template inline bool chmax(S &a, const T &b) { if (a inline bool chmin(S &a, const T &b) { if (b ostream &operator << (ostream &os, const pair< T1, T2 > &p) { os << p.first << " " << p.second; return os; } template< typename T1, typename T2 > istream &operator >> (istream &is, pair< T1, T2 > &p) { is >> p.first >> p.second; return is; } template< typename T1, typename T2, typename T3 > ostream &operator << (ostream &os, const tuple< T1, T2, T3 > &t) { os << get<0>(t) << " " << get<1>(t) << " " << get<2>(t); return os; } template< typename T1, typename T2, typename T3 > istream &operator >> (istream &is, tuple< T1, T2, T3 > &t) { is >> get<0>(t) >> get<1>(t) >> get<2>(t); return is; } template< typename T > ostream &operator << (ostream &os, const vector< T > &v){ for (int i = 0; i < (int)v.size(); ++i) { os << v[i] << (i + 1 != v.size() ? " " : ""); } return os; } template< typename T > istream &operator >> (istream &is, vector< T > &v){ for(T &in : v) is >> in; return is; } /*--------------------------------- Tools ------------------------------------------*/ template< typename T > vector cumsum(const vector &X){ vector res(X.size() + 1, 0); for(int i = 0; i < X.size(); ++i) res[i + 1] += res[i] + X[i]; return res; } template< typename S, typename T, typename F> pair bisearch(S left, T right, F f) { while(abs(right - left) > 1){ T mid = (right + left) / 2; if(f(mid)) right = mid; else left = mid; } return {left, right}; } template< typename S, typename T, typename F> double trisearch(S left, T right, F f, int maxLoop = 90){ double low = left, high = right; while(maxLoop--){ double mid_left = high / 3 + low * 2 / 3; double mid_right = high * 2 / 3 + low / 3; if(f(mid_left) >= f(mid_right)) low = mid_left; else high = mid_right; } return (low + high) * 0.5; } /*--------------------------------- Graph ------------------------------------------*/ struct Edge { ll from, to, weight; Edge() : from(0), to(0), weight(0) {} Edge(ll f, ll t, ll w) : from(f), to(t), weight(w) {} }; using Edges = vector; using Graph = vector; void add_edge(Graph &g, ll a, ll b, ll w = 1){ g[a].emplace_back(a, b, w); g[b].emplace_back(b, a, w); } void add_arrow(Graph &g, ll a, ll b, ll w = 1){ g[a].emplace_back(a, b, w); } template< typename T > vector dijkstra(Graph &g, T s, bool restore = false){ vector dist(g.size(), INF); priority_queue, vector>, greater>> que; dist[s] = 0; que.emplace(dist[s], s); vector prev(g.size(), -1); while(!que.empty()){ T cost, idx; tie(cost, idx) = que.top(); que.pop(); if(dist[idx] < cost) continue; for(auto &e : g[idx]){ auto next_cost = cost + e.weight; if(dist[e.to] <= next_cost) continue; dist[e.to] = next_cost; if(restore) prev[e.to] = e.from; que.emplace(dist[e.to], e.to); } } if(restore) return prev; return dist; } vector shortest_path(Graph &g, ll start, ll goal){ vector prev = dijkstra(g, start, true); vector path; for (int cur = goal; cur != -1; cur = prev[cur]) path.push_back(cur); reverse(path.begin(), path.end()); return path; } /*------------------------------- Main Code Here -----------------------------------------*/ int main() { ll N, V, L; cin >> N >> V >> L; vector> X(N); cin >> X; vec2 f(N + 1, vec(V + 1, INF)); rep(j, V + 1) f[0][j] = 0; ll prev = 0; rep1(i, N){ auto [x, v, w] = X[i - 1]; ll dist = x - prev; prev = x; rep(j, V + 1) if(j + dist <= V){ chmin(f[i][j], f[i - 1][j + dist]); chmin(f[i][min(V, j + v)], f[i - 1][j + dist] + w); } } ll ans = INF; ll last = get<0>(X.back()); rep(j, V) if(j >= L - last) chmin(ans, f[N][j]); print(ans == INF ? -1 : ans); return 0; }