#include using namespace std; #define REP(i,a,n) for(int i=(a); i<(int)(n); i++) #define rep(i,n) REP(i,0,n) #define FOR(it,c) for(__typeof((c).begin()) it=(c).begin(); it!=(c).end(); ++it) #define ALLOF(c) (c).begin(), (c).end() typedef long long ll; typedef unsigned long long ull; static const long long mod = 1000000007; struct mint { long long x; mint(ll x = 0):x(x%mod) {} mint& operator+=(const mint a) { (x += a.x) %= mod; return *this; } mint& operator-=(const mint a) { (x += mod-a.x) %= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { mint ret(*this); return ret += a; } mint operator-(const mint a) const { mint ret(*this); return ret -= a; } mint operator*(const mint a) const { mint ret(*this); return ret *= a; } mint pow(ll t) const { if(t==0) return mint(1); mint a = pow(t>>1); a *= a; if(t&1) a *= *this; return a; } //for prime mod mint inv() const { return pow(mod-2); } mint& operator/=(const mint a) { return (*this) *= a.inv(); } mint operator/(const mint a) const { mint ret(*this); return ret /= a; } }; ostream &operator<<(ostream& os, const mint& x) { os << x.x; return os; } class modutils { vector fact, invfact; public: modutils(int n = 200005):fact(n+1),invfact(n+1) { fact[0] = 1; for(int i=1; i<=n; i++) fact[i] = fact[i-1] * i; invfact[n] = fact[n].inv(); for(int i=n; i>=1; i--) invfact[i-1] = invfact[i] * i; } mint pow(mint x, ll n) { return x.pow(n); } mint comb(ll n, ll k) { if(n<0 || k<0 || n> N >> M; vector v, w; rep(i,N){ int a; cin >> a; v.push_back(a); } rep(i,M){ int a; cin >> a; w.push_back(a); } int A, B; cin >> A >> B; vector> dpV(105, vector(100005, 0)); dpV[0][0] = 1; rep(i,v.size()){ rep(j,100005){ dpV[i+1][j] += dpV[i][j]; if(j+v[i]<100005) dpV[i+1][j + v[i]] += dpV[i][j]; } } vector> dpR(105, vector(100005, 0)); dpR[0][0] = 1; rep(i,w.size()){ rep(j,100005){ dpR[i+1][j] += dpR[i][j]; if(j+w[i]<100005) dpR[i+1][j + w[i]] += dpR[i][j]; } } vector sumR(100005, 0); REP(i,1,100005) sumR[i] = sumR[i-1] + dpR[M][i]; mint ret(0); REP(i,1,100005){ mint cnt = dpV[N][i]; int lhs = max(0, (i+B-1) / B - 1); int rhs = i / A; ret += cnt * (sumR[rhs] - sumR[lhs]); } cout << ret << endl; return 0; }