#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#define all(x) (x).begin(),(x).end()
//#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60;
template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
//---------------------------------------------------------------------------------------------------
/*---------------------------------------------------------------------------------------------------
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---------------------------------------------------------------------------------------------------*/














int N, ABC[16][3];
int dp[1 << 16][16][3];
bool ok[16][3][16][3];
//---------------------------------------------------------------------------------------------------
void _main() {
	cin >> N;
	rep(i, 0, N) rep(j, 0, 3) cin >> ABC[i][j];

	rep(lst, 0, N) rep(hei, 0, 3) rep(nxt, 0, N) rep(hei2, 0, 3) {
		vector<int> other;
		rep(j, 0, 3) if (hei != j) other.push_back(ABC[lst][j]);
		sort(all(other));

		vector<int> other2;
		rep(j, 0, 3) if (hei2 != j) other2.push_back(ABC[nxt][j]);
		sort(all(other2));

		do {
			do {
				if (other2[0] <= other[0] && other2[1] <= other[1]) ok[lst][hei][nxt][hei2] = true;
			} while (next_permutation(all(other2)));
		} while (next_permutation(all(other)));
	}

	rep(msk, 0, 1 << N) rep(lst, 0, N) rep(hei, 0, 3) dp[msk][lst][hei] = -1;
	rep(lst, 0, N) rep(hei, 0, 3) dp[1 << lst][lst][hei] = ABC[lst][hei];

	rep(msk, 0, 1 << N) rep(lst, 0, N) rep(hei, 0, 3) if (0 <= dp[msk][lst][hei]) {
		rep(nxt, 0, N) if (!(msk & (1 << nxt))) rep(hei2, 0, 3) {
			if (ok[lst][hei][nxt][hei2]) {
				int msk2 = msk | (1 << nxt);
				chmax(dp[msk2][nxt][hei2], dp[msk][lst][hei] + ABC[nxt][hei2]);
			}
		}
	}

	int ans = -1;
	rep(msk, 0, 1 << N) rep(lst, 0, N) rep(hei, 0, 3) chmax(ans, dp[msk][lst][hei]);
	cout << ans << endl;
}